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sergejj [24]
3 years ago
6

What is the measurement for this angle?

Mathematics
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

B

Step-by-step explanation:

150 degrees

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Sean took 4 hours to travel from Town A to Town B at an
labwork [276]

Answer:

Tina's average speed  for the whole journey = 56 kmph

Step-by-step explanation:

Time taken by Sean to travel from Town A to Town B = 4 hours.

Average speed of Sean = 70 km/h

We have equation of motion, s = ut + 0.5 at²

Time, t = 4 hours.

Initial speed, u = 70 km/hr

Acceleration, a = 0 m/s²

Substituting

      s = ut + 0.5 at²

      s = 70 x 4 + 0.5 x 0 x  4²

       s = 280 km

Distance from Town A to Town B = 280 km

Tina took 1 hour more than Sean.

Time taken by Tina to travel from Town A to Town B = 4 +1 = 5 hours

We have equation of motion, s = ut + 0.5 at²

Time, t = 5 hours.

Displacement, s = 280 km

Acceleration, a = 0 m/s²

Substituting

      s = ut + 0.5 at²

      280 = u x 5 + 0.5 x 0 x  5²

       u = 56 km/hr

Tina's average speed  for the whole journey = 56 kmph

6 0
3 years ago
Please help me with this problem​
Marina CMI [18]

Answer:

A) sin 70 = x/10

Step-by-step explanation:

From the angle 70 degrees, 10 is the hypotenuse and x is the opposite and if we go by SOH-CAH-TOA I have an O and a H so its sin.

so we know it's sin so we need to figure out the equation. since we have a hypotenuse as a factor it is on top. and the other number is on the bottom.

so,

A) sin 70 = x/10

7 0
3 years ago
Let X1 and X2 be independent random variables with mean μand variance σ².
My name is Ann [436]

Answer:

a) E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu

So then we conclude that \hat \theta_1 is an unbiased estimator of \mu

E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu

So then we conclude that \hat \theta_2 is an unbiased estimator of \mu

b) Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}

Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}

Step-by-step explanation:

For this case we know that we have two random variables:

X_1 , X_2 both with mean \mu = \mu and variance \sigma^2

And we define the following estimators:

\hat \theta_1 = \frac{X_1 + X_2}{2}

\hat \theta_2 = \frac{X_1 + 3X_2}{4}

Part a

In order to see if both estimators are unbiased we need to proof if the expected value of the estimators are equal to the real value of the parameter:

E(\hat \theta_i) = \mu , i = 1,2

So let's find the expected values for each estimator:

E(\hat \theta_1) = E(\frac{X_1 +X_2}{2})

Using properties of expected value we have this:

E(\hat \theta_1) =\frac{1}{2} [E(X_1) +E(X_2)]= \frac{1}{2} [\mu + \mu] = \mu

So then we conclude that \hat \theta_1 is an unbiased estimator of \mu

For the second estimator we have:

E(\hat \theta_2) = E(\frac{X_1 + 3X_2}{4})

Using properties of expected value we have this:

E(\hat \theta_2) =\frac{1}{4} [E(X_1) +3E(X_2)]= \frac{1}{4} [\mu + 3\mu] = \mu

So then we conclude that \hat \theta_2 is an unbiased estimator of \mu

Part b

For the variance we need to remember this property: If a is a constant and X a random variable then:

Var(aX) = a^2 Var(X)

For the first estimator we have:

Var(\hat \theta_1) = Var(\frac{X_1 +X_2}{2})

Var(\hat \theta_1) =\frac{1}{4} Var(X_1 +X_2)=\frac{1}{4} [Var(X_1) + Var(X_2) + 2 Cov (X_1 , X_2)]

Since both random variables are independent we know that Cov(X_1, X_2 ) = 0 so then we have:

Var(\hat \theta_1) =\frac{1}{4} [\sigma^2 + \sigma^2 ] =\frac{\sigma^2}{2}

For the second estimator we have:

Var(\hat \theta_2) = Var(\frac{X_1 +3X_2}{4})

Var(\hat \theta_2) =\frac{1}{16} Var(X_1 +3X_2)=\frac{1}{4} [Var(X_1) + Var(3X_2) + 2 Cov (X_1 , 3X_2)]

Since both random variables are independent we know that Cov(X_1, X_2 ) = 0 so then we have:

Var(\hat \theta_2) =\frac{1}{16} [\sigma^2 + 9\sigma^2 ] =\frac{5\sigma^2}{8}

7 0
3 years ago
Using an inequality symbol (<,>,=,=) to compare 5 + (-4) _____ 14 + (-13)
Olegator [25]
Well, both sides are equal to 1, so I'm thinking "="
8 0
3 years ago
(FREE BRAINLIEST) The difference of two numbers is 4 and their sum is 14. What is their product?
Verizon [17]

Answer:

9x5=45

Step-by-step explanation:

i used my brain

:)

8 0
3 years ago
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