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sergejj [24]
3 years ago
6

What is the measurement for this angle?

Mathematics
1 answer:
adelina 88 [10]3 years ago
3 0

Answer:

B

Step-by-step explanation:

150 degrees

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stiv31 [10]
5x + 3 \geq 23
5x \geq 20
x \geq 4
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4 years ago
Solve for x: <br>5x - 3y = 22<br> 10x - 4y = 46​
Alik [6]

Answer:

x=5, y=1

Step-by-step explanation:

Isolate x for 5x-3y=22

5x-3y=22

Add 3y to both sides

5x-3y+3y=22+3y

Simplify

5x=22+3y

Divide both sides by 5

5x/5=22/5+3y/5

Simplify

x=22+3y/5

Substitute  x=22+3y/5

10*22+3y/5-4y=46

Simplify 10*22+3y/5-4y

10*22+3y/5=2(3y+22)

=2(3y+22)-4y

Expand 2(3y+22)

=6y+44-4y

Simplify 6y+44-4y

=2y+44

Isolate y for 2y+44=46

2y+44=46

Subtract 44 from both sides:

2y+44-44=46-44

Simplify

2y=2

Divide both sides by 2;

2y/2=2/2

Simplify;

y=1

For x=22+3*1/5 substitute y=1

y=22+3*1/5

22+3*1=25

=25/5

Divide the numbers;25/5=5

=5

x=5

The solutions to the system of equations are;

x=5, y=1

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Which of the following angle relationships in △ABC are correct? Select all that apply.
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m < B = m < C

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3 years ago
A standard deck of cards contains 52 cards. One card is selected from the deck. ​(a) Compute the probability of randomly selecti
Masja [62]

Answer:

a) 1/2 = 50%

b) 3/4 = 75%

c)  1 / 52 or 1,9%

Step-by-step explanation:

In a standard deck of cards, there are 52 cards in total:

13 are hearts, 13 are diamonds, 13 are clubs and 13 are spades.

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How many cards are a club or a spade?

C = 13 clubs + 13 spades = 26 cards

Out of the 52 total, that means that:

P (club or spade) = 26/52 = 1/2 = 50%

​(b) Compute the probability of randomly selecting a club or spade or heart. ​

How many cards are a club or a spade?

C = 13 clubs + 13 spades  + 13 hearts = 39 cards

Out of the 52 total, that means that:

P (club or spade or heart) = 39/52 = 3/4 = 75%

(c) Compute the probability of randomly selecting a two or diamond.

There's only ONE two of diamond in  regular deck of cards, so...

P(2 of diamond) = 1 / 52 or 1,9%

7 0
3 years ago
Solve the following equation for r2: Q = 2sL(T2-T1)/ln(r2/r1)
Sergeu [11.5K]
Q=2*s*L(T2-T1)/ (R2/R1)
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R2=0.6072.
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3 years ago
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