Let's simplify step-by-step.
o25n−3(n−6)
Distribute:
=o25n+(−3)(n)+(−3)(−6)
=no25+−3n+18
Answer:
=no25−3n+18
(Pls mark as brainliest) (:
Answer:
7. A = 40.8 deg; B = 60.6 deg; C = 78.6 deg
8. A = 20.7 deg; B = 127.2 deg; C = 32.1 deg
Step-by-step explanation:
Law of Cosines

You know the lengths of the sides, so you know a, b, and c. You can use the law of cosines to find C, the measure of angle C.
Then you can use the law of cosines again for each of the other angles. An easier way to solve for angles A and B is, after solving for C with the law of cosines, solve for either A or B with the law of sines and solve for the last angle by the fact that the sum of the measures of the angles of a triangle is 180 deg.
7.
We use the law of cosines to find C.






Now we use the law of sines to find angle A.
Law of Sines

We know c and C. We can solve for a.


Cross multiply.





To find B, we use
m<A + m<B + m<C = 180
40.8 + m<B + 78.6 = 180
m<B = 60.6 deg
8.
I'll use the law of cosines 3 times here to solve for all the angles.
Law of Cosines



Find angle A:





Find angle B:





Find angle C:





Amount Daisy plans to spend on food is $625
Step-by-step explanation:
- Step 1: Given total savings of Daisy = $5000. Find the amount spent by Daisy on her room
Amount spent on room = 3/4 of 5000 = 3/4 × 5000 = $3750
- Step 2: Calculate the remaining amount.
Remaining amount = $5000 - $3750 = $1250
- Step 3: Calculate the amount Daisy plans to spend on food
Amount to be spend on food = 1/2 of 1250 = 1/2 × 1250 = $625
Answer:
Every 200 visitors, the visitor will receive all 4 gifts.
Step-by-step explanation:
With the given numbers, the lowest common number would be 200.
Answer:
Sum of the opposite pair of a cyclic quadrilateral is 180°.
c= 180-102= 78°
c= 180-102= 78°d= 180-92= 88°
<em><u>intercepted arc</u></em>
=>2(102°)= 140+a°
a=64°
<u>Simillarly</u>
=> 2(d°)= a°+b°
b°= 112°
so ....
<u>a=64°</u>
<u>a=64°b=112°</u>
<u>a=64°b=112°c=78°</u>
<u>a=64°b=112°c=78°d=88</u>
<em><u>hope it helps you</u></em><u> </u><u>.</u><u>.</u><u>.</u><u>.</u>