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3 years ago

What is the slope of a line that is perpendicular to the line: -4x + 6y = -1 ?

Mathematics

1 answer:

elena-s [515]3 years ago

3 0

Your answer should be 2/3

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What is 10:40 plus 7:15 in time?

sp2606 [1]

Answer:

5:55

Step-by-step explanation:

10 plus 7 in time is 5 and 15 plus 40 is 55

4 0

3 years ago

Read 2 more answers

Use quadratic formula to solve 1-6x^2-x

eduard

Answer:

(3x-1)(2x+1)

Step-by-step explanation:

1-6x^2-x=0

-6x^2-x+1=0

6x^2+x-1=0

6x^2+(3-2)x-1=0

6x^2+3x-2x-1=0

3x(2x+1)-1(2x+1)=0

(3x-1)(2x+1)=0

So the factor is (3x-1)(2x+1)

6 0

3 years ago

How do you name a vector?

Llana [10]

You can name a vector<span> by its length and direction</span>

8 0

3 years ago

Solve x2 – 7x = –13.

aleksklad [387]

we have

$x^{2} -7x=-13$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} -7x+3.5^{2}=-13+3.5^{2}$

$x^{2} -7x+12.25=-13+12.25$

$x^{2} -7x+12.25=-0.75$

Rewrite as perfect squares

$(x-3.5)^{2}=-0.75$

remember that

$i=\sqrt{-1}$

Square root both sides

$(x-3.5)=(+/-)\sqrt{-0.75}$

$(x-3.5)=(+/-)\sqrt{-1*0.75}$

$(x-3.5)=(+/-)\sqrt{0.75}i$

$x1=3.5+\sqrt{0.75}i$

$x2=3.5-\sqrt{0.75}i$

Simplify

$\sqrt{0.75}=\frac{\sqrt{3}}{2}$

$x1=3.5+\frac{\sqrt{3}}{2}i$

$x2=3.5-\frac{\sqrt{3}}{2}i$

therefore

<u>the answer is</u>

$x1=3.5+\frac{\sqrt{3}}{2}i$

$x2=3.5-\frac{\sqrt{3}}{2}i$

6 0

3 years ago

Read 2 more answers

This is me and I am proud of my 15 year old self

almond37 [142]

Answer:

good

Step-by-step explanation:

thx for the points :)

7 0

3 years ago