[( 91 * 10^-1 ) *10^ -5]^-4 = (91 * 10^-6)^-4 = 91^-4 * 10^24 = ( 10^24 )/ ( 91^4 ) =
10000000 ≈ 1458258211769
Step by step:
Perimeter = Summation of all sides = AB+BC+CD+DA = 2x+2+x+2x+2+x=(6x+4)
⇒6x+4=154
⇒6x=154−4
⇒
⇒25=x
The breadth is x=25
The length of the rectangular pool = (2×25+2)=50+2=52m
<em>breadth </em>is 25 and the<em> length </em>is 52
Hope it helps!
Let, one leg be x units.
since the other leg is 9.0 units shorter than the other,
the measure of the other leg =x-9
hypotenuse =13.0 units
According to Pythagorean theorem, the square of the hypotenuse is equal to the sum of squares of the other two sides.
x^2 +(x-9)^2 =13^2
x^2 + x^2 -18x +81 = 169
2x^2-18x-88=0
Divide the whole equation by 2
x^2 - 9x -44 =0
Let's use the quadratic formula to find the roots.
formula: x= [-b ± sqrt(b^2-4*a*c)]/2*a
a=1 b=-9 c=-44
x= [9±sqrt(81+176)]/2
=[9±sqrt(257)]/2
=[9±16.03]/2
=25.03/2 or -7.03/2
length of a triangle cannot be negative,
Therefore, x=25.03/2 =12.52
one leg =12.5 units
other leg =12.52-9 =3.5 units
