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A. The perimeter of quadrilaterals are same when x=2.
B. The area of quadrilaterals are same when x=4.6
<u>Step-by-step explanation</u>:
A. <u>Perimeter of the quadrilaterals must be equal.</u>
- Perimeter of square is 4a.
- where, a = 6
- Perimeter of rectangle is 2(l+b).
- where, l = 2 and b = (3x+4)
Perimeter of square = Perimeter of rectangle
4(6) = 2(2+3x+4)
⇒ 24 = 2(3x+6)
⇒ 24 = 6x + 12
⇒ 6x = 12
⇒ x = 12/6
x = 2
For x=2, the perimeters of both the quadrilaterals are same.
B. <u>Area of the quadrilaterals must be equal.</u>
- Area of square is a².
- where, a = 6.
- Area of rectangle is l
b.
- where, l = 2 and b = (3x+4)
Area of square = Area of rectangle
(6)² = 2(3x+4)
36 = 6x+8
6x = 28
x = 28/6
x = 4.6
For x=4.6, the area of both the quadrilaterals are same.
Answer:
See below.
Step-by-step explanation:
First, we can see that .
Thus, for the question, we can just plug -1 in:
Saying undefined (or unbounded) will be correct.
However, note that as x approaches 2, the values of y decrease in order to get to -1. In other words, will always be greater or equal to -1 (you can also see this from the graph). This means that as x approaches 2, f(x) will approach -.99 then -.999 then -.9999 until it reaches -1 and then go back up. What is important is that because of this, we can determine that:
This is because for the denominator, the +1 will always be greater than the f(x). This makes this increase towards positive infinity. Note that limits want the values of the function as it approaches it, not at it.
It is ROOT 34. Therefore none of the above.
