Answer:
No for the first one, yes for the second.
Step-by-step explanation:
Plug in the given numbers and see if it works.
15(1) + 3(4) = 10
15 + 12 = 10.
27 ≠ 10
Since 27 does not equal 10, we can already see that solution (1,4) will not work for these equations.
Now for the second problem, do the same thing.
10 = 1 + 9.
This is true, but remember to check the second equation just to be sure.
10 = 4(1) + 6
10 = 4 + 6
This is also true, so it (1,10) is a solution for the second system of equations.
Answer:
• discriminant: 73
• # of real solutions: 2
Step-by-step explanation:
Comparing the equation ...
2x^2 -9x +1 = 0
to the generic form ...
ax^2 +bx +c = 0
we find the coefficient values to be ...
a = 2; b = -9; c = 1
That makes the value of the discriminant, (b^2 -4ac), be ...
(-9)^2 -4(2)(1) = 81 -8 = 73
Since the discriminant is positive, the number of real solutions is 2.
I think that the answer is about 2,880 cars.
Answer:
The correct answer is;
ΔANT ≅ ΔFLE by the SIde-Side-Side (SSS) rule of congruency
Step-by-step explanation:
The given information are;
Segment TN is congruent ts segment EL
Segment TA is congruent ts segment EF
Segment AN is congruent ts segment FL
Therefore, triangle ΔANT is congruent to ΔFLE by the Side-Side-Side (SSS) rule of congruency
One of the rule used to serve as proof that two or more triangles are congruent, is the Side-Side-Side (SSS) rule of congruency. The Side-Side-Side rule of congruency states that if the dimensions of the three sides of one triangle are equal to the dimensions of the three sides of another triangle, the two triangles are congruent.
Therefore, the correct option is ΔANT ≅ ΔFLE by the Side-Side-Side (SSS) rule of congruency
First, you substitute each x in the first equation- 2(2y+10)-3y=17
Next, simplify - 4y+20-3y=17
y+20=17
y=-3
Next, substitute the y in for the second equation, x=2y+10
x=2(-3)+10
x=-6+10
x=4
ANswer:
x=4
y=-3
Hope this helps!
