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hichkok12 [17]
3 years ago
6

10) using opposite operations solve for x 30 = - 6 x + 12

Mathematics
1 answer:
Len [333]3 years ago
7 0
X=-3 that’s the answer your welcome
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What is the value of the discriminante for the quadratic equation 0=2x^+x-3
denpristay [2]

Answer:

x1= 1 , x2 = (-1.5)

Step-by-step explanation:

If you have any questions about the way I solved it, don't hesitate to ask me ;}

8 0
3 years ago
Two sides of a triangle are exactly the Same length. The length of the third side is four cm shorter than the two equal sides. F
liubo4ka [24]

Answer:

15 cm, 15 cm, 11 cm

Step-by-step explanation:

let the equal sides be x then the third side is x - 4

The perimeter is the sum of the 3 sides and is 41 cm , then

x + x + x - 4 = 41

3x - 4 = 41 ( add 4 to both sides )

3x = 45 ( divide both sides by 3 )

x = 15

x - 4 = 15 - 4 = 11

The sides are 15 cm, 15 cm, 11 cm

3 0
2 years ago
I am very stuck with this
Bingel [31]

Answer:

see explanation

Step-by-step explanation:

To multiply the vector by a scalar, multiply each of the elements by the scalar.

To add 3 vectors add the corresponding elements of each vector

2a + 3b + 4c

= 2\left[\begin{array}{ccc}2\\3\\\end{array}\right] + 3\left[\begin{array}{ccc}-4\\1\\\end{array}\right] + 4\left[\begin{array}{ccc}3\\2\\\end{array}\right]

= \left[\begin{array}{ccc}4\\6\\\end{array}\right] + \left[\begin{array}{ccc}-12\\3\\\end{array}\right] + \left[\begin{array}{ccc}12\\8\\\end{array}\right]

= \left[\begin{array}{ccc}4-12+12\\6+3+8\\\end{array}\right]

= \left[\begin{array}{ccc}4\\17\\\end{array}\right]

8 0
3 years ago
A batch of 580 containers for frozen orange juice contains 8 that are defective. Two are selected, at random, without replacemen
serious [3.7K]

Answer:

a. 0.12109

b. 0.0001668

c .0.9726

d. 0.01038

e. 0.01211

f. 0.000001731

Step-by-step explanation:

Sample size = 580

Defective units = 8

Number of picks = 2

a) If the first container is defective, there 7 defective containers left in a population of 579. The probability of selecting a defective one is:

P=\frac{7}{579}=0.121

b) The probability that both are defective is given by:

P=\frac{8}{580}*\frac{7}{579}= 0.000167

c) The probability that both are acceptable is given by:

P=\frac{580-8}{580}*\frac{579-8}{579}= 0.9726

d) In this case, two defective units were removed from the batch, the probability that the third is also defective is:

P=\frac{6}{578}}= 0.0104

e) In this case, one acceptable and one defective unit were removed from the batch, the probability that the third is also defective is:

P=\frac{7}{578}= 0.01211

f) The probability that all three are defective is given by:

P=\frac{8}{580}*\frac{7}{579}*\frac{6}{578} = 0.000001731

7 0
3 years ago
Which equation represents, the result when 0.0077 is the product of g and 1.1?
Serjik [45]
<span>g = 0.00847 i think ok</span>
8 0
3 years ago
Read 2 more answers
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