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Leto [7]
3 years ago
10

What scale factor was applied to the first rectangle to get the result image?

Mathematics
2 answers:
sleet_krkn [62]3 years ago
8 0
I dont know what the images are but scale factor is <span>is a number which </span>scales<span>, or multiplies, some quantity. Technically it is the number you have to multiply on each side that will get you the sides on the smaller or larger rectangle!!!

I hope it helps!!!
- Amana</span>
aksik [14]3 years ago
4 0

Answer:

Step-by-step explanation: Add pic so ppl can help

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Triangle MNP has vertices M(5,4), N(5,9), and P(−1,4). What are the coordinates of the image of point P after the triangle is ro
Diano4ka-milaya [45]

Answer:

P' (1, -4)

Step-by-step explanation:

Hey girl, your pfp be making me want you a lott.

5 0
2 years ago
If anyone would like a quick response to their question im happy to help :) it can be about anything
IgorLugansk [536]

Answer:

I could really use some help on a question that I am struggling with. Can you help? Here it is...

Step-by-step explanation:

What is the interest on $3,500 borrowed for two years at 2.5% interest?

4 0
3 years ago
N = 9
g100num [7]

Answer:

The <em>p</em>-value is 0.809.

Step-by-step explanation:

In this case we need to perform a significance test for the standard deviation.

The hypothesis is defined as follows:

<em>H</em>₀: <em>σ</em>₀ = 4 vs. <em>Hₐ</em>: <em>σ</em>₀ ≤ 4

The information provided is:

<em>n</em> = 9

<em>s</em> = 3

Compute the Chi-square test statistic as follows:

\chi^{2}=\frac{(n-1)s^{2}}{\sigma_{0}^{2}}

     =\frac{(9-1)\cdot (3)^{2}}{(4)^{2}}\\\\=\frac{8\times 9}{16}\\\\=4.5

The test statistic value is 4.5.

The degrees of freedom is:

df = n - 1

   = 9 - 1

   = 8

Compute the <em>p</em>-value as follows:

p-value=P(\chi^{2}_{9}>4.5)=0.809

*Use a Chi-square table.

Thus, the <em>p</em>-value is 0.809.

7 0
3 years ago
Simplify the equation
pashok25 [27]

Answer:

I think that the answer is C. 9^24

6 0
3 years ago
EASY QUESTION
Ostrovityanka [42]
The correct answer would be D, the median 86.5.

In this set of data most of the values are in the 80's or 90's. There is only 1 number that is outside of this range, that is the value 0. It is an outlier. 

When we have an outlier, the median generally gives us the better measure of central tendency.
6 0
3 years ago
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