Answer:
(u+2)(2a+9)
Step-by-step explanation:
2a(u+2)+9(u+2)
Taking (u+2) common
We get
(u+2)(2a+9)
A
No you cannot use HL to prove the triangles are congruent because there is no way to know if the hypotenuses of BE and EC are congruent
Answer:
32/8=4+3+4+3 =24
Step-by-step explanation:
I turn the mixed numbers into decimals before doing anything else.
11 2/5----> 57/5----> 11.4
4 2/7----> 30/7----> 4.29
2 1/7----> 15/7----> 2.14
11.4=q-4.29+2.14
11.4=q-2.15
13.55= q
13.55 converted to a fraction is 13 11⁄20
q=13 11⁄20
If this helps 3x3=9 .........................