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sergejj [24]
3 years ago
12

Find the distance point between ( 0,0 ) and ( 4,3 )

Mathematics
1 answer:
Rzqust [24]3 years ago
5 0

Answer: The distance between the two points is 5.

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(a) By inspection, find a particular solution of y'' + 2y = 14. yp(x) = (b) By inspection, find a particular solution of y'' + 2
SOVA2 [1]

Answer:

(a) The particular solution, y_p is 7

(b) y_p is -4x

(c) y_p is -4x + 7

(d) y_p is 8x + (7/2)

Step-by-step explanation:

To find a particular solution to a differential equation by inspection - is to assume a trial function that looks like the nonhomogeneous part of the differential equation.

(a) Given y'' + 2y = 14.

Because the nonhomogeneus part of the differential equation, 14 is a constant, our trial function will be a constant too.

Let A be our trial function:

We need our trial differential equation y''_p + 2y_p = 14

Now, we differentiate y_p = A twice, to obtain y'_p and y''_p that will be substituted into the differential equation.

y'_p = 0

y''_p = 0

Substitution into the trial differential equation, we have.

0 + 2A = 14

A = 6/2 = 7

Therefore, the particular solution, y_p = A is 7

(b) y'' + 2y = −8x

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x

2Ax + 2B = -8x

By inspection,

2B = 0 => B = 0

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x

(c) y'' + 2y = −8x + 14

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = -8x + 14

2Ax + 2B = -8x + 14

By inspection,

2B = 14 => B = 14/2 = 7

2A = -8 => A = -8/2 = -4

The particular solution y_p = Ax + B

is -4x + 7

(d) Find a particular solution of y'' + 2y = 16x + 7

Let y_p = Ax + B

y'_p = A

y''_p = 0

0 + 2(Ax + B) = 16x + 7

2Ax + 2B = 16x + 7

By inspection,

2B = 7 => B = 7/2

2A = 16 => A = 16/2 = 8

The particular solution y_p = Ax + B

is 8x + (7/2)

8 0
3 years ago
A football team loses 3 yards on one play and 6 yards on another play write a sum of negative intergers to represent this situat
andrew11 [14]
6-3-3=-0 its - cause 3+3=6 and if 3-6-3 is o but its already o then just put a little line net to the zero
7 0
3 years ago
In your own words, write the steps used for constructing tangent lines to a circle from a point outside the circle with only a c
pishuonlain [190]
Paraphrase the following steps:

•Draw a line connecting the point to the center of the circle
•Construct the perpendicular bisector of that line
•Place the compass on the midpoint, adjust its length to reach the end point, and draw an arc across the circle
•Where the arc crosses the circle will be the tangent points.
6 0
3 years ago
Pleaseee helppp!!! I'll give brainliestt!!<br><br> AND<br> please don't just answer for points!
kvasek [131]

Answer:

x=-8 where A=1 and B=0

Step-by-step explanation:

The given line's graph is x=-8. Since there is no y, they coefficient in front of y, B, will be 0, and since there is only one x, that coefficient in front of the x, A, will be 1.

5 0
2 years ago
Read 2 more answers
How many times does 2 go into 18 and how many times does 3 go into 27
gregori [183]
2 goes into 18 nine times.
3 goes into 27 nine times.
4 0
3 years ago
Read 2 more answers
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