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3 years ago

7

10 times as much as 2000 is 1 tenth of

1 answer:

Pani-rosa [81]3 years ago

7 0

10 times as much as 2000 is 1/10 of 200,000. I believe.

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Solve and graph -12 <= x - 6 <= -2

Levart [38]

Answer:

4780373 ykitttuyyu

Step-by-step explanation:

brugegentug yktgdcm vylkg

6 0

3 years ago

Simplify -12x^4/x^4+8x^5

alexgriva [62]

Answer:

OPTION A: $\frac{12}{1 + 8x}$ , where $x \ne - \frac{1}{8}$ .

Step-by-step explanation:

Given: $\frac{- 12x^4}{x^4 + 8x^5}$

Taking $x^4$ common outside in the denominator, we get:

$= \frac{-12x^4}{(x^4)(1 + 8x)}$

$x^4$ will get cancelled on the numerator and denominator, we get:

$= \frac{-12}{1 + 8x}$

we know that the denominator can not be zero.

That means, 1 + 8x $\ne$ 0.

$\implies 8x \ne -1$

$\implies x \ne \frac{-1}{8}$

So, the answer is: $\frac{-12}{1 + 8x}$ , where $x \ne \frac{-1}{8}$ .

6 0

4 years ago

One positive number is 9 more than twice another. If their product is 95, find the numbers.

mafiozo [28]

Answer:

The numbers are 19 and 5

Step-by-step explanation:

Given

Let the numbers be $x\ and\ y.$

So:

$x = 9 + 2y$ --- First statement

$x*y = 95$ --- second statement

Required

Find x and y

Substitute $x = 9 + 2y$ in $x*y = 95$

$(9 + 2y) * y = 95$

$9y + 2y^2 = 95$

Rewrite as:

$2y^2 + 9y - 95 = 0$

Expand

$2y^2 -10y +19y- 95 = 0$

Factorize

$2y(y -5) +19(y- 5) = 0$

$(2y +19)(y- 5) = 0$

Solve for y

$2y + 19 =0$ or $y - 5 = 0$

$2y = -19$ or $y = 5$

$y = -\frac{19}{2}$ or $y=5$

Since the numbers are positive, we take only:

$y=5$

Substitute $y=5$ in $x = 9 + 2y$

$x = 9 + 2 * 5$

$x = 9 + 10$

$x = 19$

<em>The numbers are 19 and 5</em>

5 0

3 years ago

What percent of 26 is 12

hichkok12 [17]

12 over 16 times 100 = 46.15 percent

5 0

3 years ago

School 1: minimum:68, Q1=77, median=83, Q3=86, maximum=95

vlada-n [284]

In school 1, 50% of the students scored above 83 and in school 2, 50% of the class scored above 81.
In school 1, 25% of the students scored above 86 and in school 2, 25% of the class scored above 85.
In school 1, 25% of the students scored below 77 and in school 2, 25% of the class scored below 73.
The minimum score for school 1 is 68 while that of school 2 is 65.
The maximum score for school 1 is 95 while that of school 2 is 98.

In all this measures of center, the data from both schools are close together, so we can conclude that both schools did abut the same on the test.

6 0

3 years ago