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Oliga [24]
4 years ago
10

HELPPPPP!!! MATH HOMEWORK. IM STUMPED.

Mathematics
1 answer:
slavikrds [6]4 years ago
3 0
First: 5
Second: 8
Third: 14

Hope this helps! :)
~Zain
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Choose the correct description of the graph of the compound inequality x − 3 < −9 or x + 5 greater than or equal to 10.
forsale [732]
X - 3 < 9    or    x + 5 ≥ 10
  + 3 + 3               - 5   - 5
     x < 12      or      x ≥ 5

Solution Set: {x|x < 12 or x ≥ 5}, (-∞, 12) or (5, ∞)
8 0
3 years ago
Read 2 more answers
mike fitness center charges $30 per month for a mrmbership .all day fitness club charges $22 per month plus an $80 initiation fe
Aliun [14]

Step-by-stm represents the number of months

Mike's: 30m

All-Day: 80 + 22m

 

30m = 80 + 22m  and im pretty sure the answer is 102

4 0
3 years ago
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
3 years ago
What is the area of a cirlcle that's 4cm ​
Elena-2011 [213]
If the radius of the circle is 4 than the area would be 50.27.

If you are saying that 4 is the diameter, than divide that by 2 to get the radius which is 2. The area for this would be 12.57.

I don’t know which one you mean but hope this helps :))
7 0
3 years ago
You roll a 6-sided die with faces numbered 1 through 6, and toss a coin. What is the probability of rolling a 2 or getting heads
tino4ka555 [31]

P(2 or H) = P(2) + P(H) - P(2 and H)  

What is the probability of getting a 2 P(2)?  = 1/6

What is the probability of getting heads P(H)?  = 1/2

P(2 and H) is the product of those two events since the events are independent. = 1/6 * 1/2 = 1/12

P(2 or H) = P(2) + P(H) - P(2 and H)  

P(2 or H) = 1/6 + 1/2  - 1/12 = 7/12

5 0
3 years ago
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