What is the value of y in the equation 4y - 2(1-y) = -442

Mathematics

1 answer:

kirill115 [55]3 years ago

8 0

Answer:

4y -2(1-y)= -442

4y -2+2y =-442

6y -2=-442

6y =-442+2

6y = -440

y = -440/6

y = - 220/3

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Rewrite the expression in terms of the given function 1/1-sinx - sinx/1+sinx

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Your question seems a bit incomplete, but for starters you can write

$\dfrac1{1-\sin x}-\dfrac{\sin x}{1+\sin x}=\dfrac{1+\sin x}{(1-\sin x)(1+\sin x)}-\dfrac{\sin x(1-\sin x)}{(1+\sin x)(1-\sin x)}=\dfrac{1+\sin x-\sin x(1-\sin x)}{(1-\sin x)(1+\sin x)}$

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and you can stop there, or continue to rewrite in terms of the reciprocal functions,

$\dfrac{1+\sin^2x}{\cos^2x}=\sec^2x+\tan^2x$

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$\sec^2x+\tan^2x=\sec^2x+(\sec^2x-1)=2\sec^2x-1$

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$\sec^2x+\tan^2x=(1+\tan^2x)+\tan^2x=1+2\tan^2x$