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Flauer [41]
3 years ago
13

Find the area of the figure

Mathematics
1 answer:
Ivenika [448]3 years ago
5 0
So it's best in this case to separate both shapes so you have a rectangle and a triangle so to solve the area of a rectangle you do
The following ( picture )
So I hope this helps

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X+y=5<br> x^y+y^x=17<br> solve for the value of y and x
pentagon [3]
X = 2 
<span>y = 3 </span>

<span>2 + 3 = 5 </span>
<span>2³ + 3² = 17 </span>

<span>------------------- </span>

<span>BUT: </span>

<span>x + y = 5 </span>
<span>x^y + y^ x = 17 </span>

<span>y = 5 - x</span>
7 0
3 years ago
Any good mathematicians out there?! In need of help<br><br> Brainliest + POINTS
Zarrin [17]

Answer:

1199 $

Step-by-step explanation:

3297+365=3662

1280+270+325+153+300+50+35= 2413

3662-2413=1249$

i hope u understand

3 0
3 years ago
Read 2 more answers
Last week you worked 7 hours more than you normally do. Your typical week totals 36 hours.What was the total number of hours you
sergejj [24]
The answer is 43 because 36 + 7 = 43
4 0
3 years ago
Read 2 more answers
What are the two solutions of 2x^2 = -X^2 - 5x - 1?
Sidana [21]

Answer:

Step-by-step explanation:

Let's solve 2x^2 = -X^2 - 5x - 1.  Consolidate all terms on the left side and write 0 on the right side:

3x^2 + 5x + 1 = 0.  This is a quadratic equation.  Let's solve it for x using the quadratic formula:

a = 3, b = 5, c = 1, and so the discriminant is b^2 - 4ac = 5^2 - 4(3)(1) = 13.  Because the discriminant is positive, we know that there are two distinct, real roots; the graphs of y = 2x^2 and y = x^2 - 5x - 1 intersect in two places whose x-coordinates are the real roots mentioned above.

Answer A is not correct as stated, but would be correct if we were to replace "the y-coordinates" with "the x-coordinates."  

Answer C would be correct if and only if we write y = x^2 - 5x - 1.

6 0
3 years ago
If c(x)=x-2 what is the value of x if c(x)=3.5
dsp73

Answer:

5.5 = x

Step-by-step explanation:

c(x)=x-2

3.5 = x-2

Add 2 to each side

3.5+2=x-2+2

5.5 = x

3 0
3 years ago
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