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Gnesinka [82]
4 years ago
13

The image of (-2, 5) is (1, 1) What is the image of (3, 2) under the same translation?

Mathematics
1 answer:
ale4655 [162]4 years ago
5 0
1st to figure out the translation!!
From (-2,5) to (1,1) 
The x values changed 3 values positive that means 3 values right 
and the y values changed 4 values negative that nears 4 values down 

So the rule is 
(x + 3 , y - 4)

(3,2) -- > (6,-2)
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A sample of a radioactive isotope had an initial mass of 360 mg in the year 1998 and
RUDIKE [14]

Answer:

193 mg

Step-by-step explanation:

Exponential decay formula:

  • A_t = A_0e^r^t
  • where Aₜ = mass at time t, A₀ = mass at time 0,  r = decay constant (rate), t = time  

Our known variables are:

  • 1998 to the year 2004 is a total of t = 6 years.
  • The sample of radioactive isotope has an initial mass of A₀ = 360 mg at time 0 and a mass of Aₜ = 270 mg at time t.

Let's solve for the decay constant of this sample.

  • 270=360e^-^r^(^6^)
  • 270=360e^-^6^r
  • \frac{3}{4} =e^-^6^r
  • \text{ln} (\frac{3}{4} )= \text{ln}(e^-^6^r)
  • \text{ln} (\frac{3}{4} )=-6r
  • r=-\frac{\text{ln}\frac{3}{4} }{6}
  • r=0.04794701

Using our new variables, we can now solve for Aₜ at t = 7 years, since we go from 2004 to 2011.

Our new initial mass is A₀ = 270 mg. We solved for the decay constant, r = 0.04794701.

  • A_t=270e^-^(^0^.^0^4^7^9^4^8^0^1^)^(^7^)
  • A_t=270e^-^0^.^3^3^5^6^2^9^0^7
  • A_t=193.01982213

The expected mass of the sample in the year 2011 would be 193 mg.

3 0
3 years ago
I need help finding the missing sides
Greeley [361]

Answer:

12

Step-by-step explanation:

15/5 = 3

4*3 = 12

d = 12

the hypotenuse is 5^{2} + 4^{2} = c^{2}

25+16 = c^{2}

41=c^{2}

\sqrt{41}

8 0
3 years ago
Read 2 more answers
What are the missing numbers?
pashok25 [27]
2.089 and 2.095 because it goes by thousandths.
7 0
3 years ago
Read 2 more answers
Y varies inversely with x. if y = 3 and k (the constant of variation) =33 what is x?
DIA [1.3K]

y = k/x

y = 3 and k = 33

y = k/x

yx = k

x = k/y

x = 33/3

x = 11

4 0
3 years ago
8. Find the scale factor of a cube with volume 729 ft3 to a cube with volume 2744 ft3
aleksandr82 [10.1K]
Let
x--------> scale factor

we know that
[smaller volume]*x³=[larger volume]
so
x=∛[larger volume/smaller volume]
x=∛[2744/729]
x=1.56

the answer is
<span>the scale factor is 1.56</span>


7 0
3 years ago
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