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3 years ago

What are the missing numbers?

Mathematics

2 answers:

pashok25 [27]3 years ago

7 0

2.089 and 2.095 because it goes by thousandths.

kogti [31]3 years ago

5 0

2.09+10x=2.1

10x=0.01

x=0.001

so each tick mark is equal to 0.001 in distance.

So the first box is 2.09-.001=2.089

And the second box is 2.09+5(.001)=2.095

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3. Write the standard equation of the circle with the given center that passes through the given

bearhunter [10]

Answer:

D is correct.

Step-by-step explanation:

(x + 2)^2 + (y - 6)^2 = r^2

(-2+2)^2 + (10 - 6)^2 = r^2

r^2= (10 - 6)^2

r^2=16

5 0

3 years ago

Round 2.56×0.03 to the nearest hundredth

Arlecino [84]

2.56 times 0.03 is 0.0768 then round to hundredth is 0.08 i think

4 0

3 years ago

In a factory, a parabolic mirror to be used in a searchlight was placed on the floor. it measured 50 centimeters tall and 90 cen

slavikrds [6]

Y=-2/81x^2+50 is the answer

7 0

3 years ago

Read 2 more answers

Question in picture A) 16/63 B)-16/63 C) 63/16 D) -63/16

Orlov [11]

ANSWER
$\tan(x + y) = - \frac{63}{16}$

EXPLANATION

We were given that,

$\csc(x) = \frac{5}{3}$

This implies that,

$\sin(x) = \frac{3}{5}$

We use the Pythagorean identity

$\sin^{2} (x) + \cos^{2} (x)= 1$
to get,

$\cos(x) = \sqrt{1 - ( { \frac{3}{5} })^{2}} = \frac{4}{5}$

We were also given that,

$\cos(y) = \frac{5}{13}$

This means that,

$\sin(y) = \sqrt{1 - {( \frac{5}{13}) }^{2} } = \frac{12}{13}$

This is because,

$0 < \: x \: < \frac{\pi}{2}$

$0 < \: y \: < \frac{\pi}{2}$

This angles are in the first quadrant so we pick the positive values.

$\tan(x + y) = \frac{ \sin(x + y) }{ \cos(x + y) }$

$\tan(x + y) = \frac{ \sin(x ) \cos(y) + \sin(y) \cos(x) }{ \cos(x) \cos(y) - \sin(x) \sin(y) }$

$\tan(x + y) = \frac{ \frac{3}{5} \times \frac{5}{13} + \frac{12}{13} \times \frac{4}{5} }{ \frac{4}{5} \times \frac{5}{13} - \frac{3}{5} \times \frac{12}{13} }$

$\tan(x + y) = - \frac{63}{16}$

The correct answer is D

4 0

3 years ago

At which of the following points do the two equations f(x)=3x2+5 and g(x)=4x+4 intersect?

Basile [38]

Answer:

( $\frac{1}{3}$ , $\frac{16}{3}$ ) and (1, 8 )

Step-by-step explanation:

To find the points of intersection equate f(x) and g(x), that is

3x² + 5 = 4x + 4 ( subtract 4x + 4 from both sides )

3x² - 4x + 1 = 0 ← in standard form

(3x - 1)(x - 1) = 0 ← in factored form

Equate each factor to zero and solve for x

3x - 1 = 0 ⇒ 3x = 1 ⇒ x = $\frac{1}{3}$

x - 1 = 0 ⇒ x = 1

Substitute these values into either of the 2 functions for corresponding y- coordinates.

Substituting into g(x), then

g(1) = 4(1) + 4 = 4 + 4 = 8 ⇒ (1, 8 )

g( $\frac{1}{3}$ ) = $\frac{4}{3}$ + 4 = $\frac{16}{3}$ ⇒ ( $\frac{1}{3}$ , $\frac{16}{3}$ )

3 0

3 years ago