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Drupady [299]
3 years ago
15

You randomly select an integer from 0 to 19 ​(inclusively) and then randomly select an integer from 0 to 24 ​(inclusively). What

is the probability of selecting 5 both​ times?
Mathematics
1 answer:
Mila [183]3 years ago
5 0

Answer:

The probability of selecting 5 both​ times is 0.002.

Step-by-step explanation:

We are given that you randomly select an integer from 0 to 19 ​(inclusively) and then randomly select an integer from 0 to 24 ​(inclusively).

And we have to find the probability of selecting 5 both​ times.

As we know that the probability of an event is given by;

                Probability = \frac{\text{Favorable number of outcomes}}{\text{Total number of outcomes}}

Now, here between integer from 0 to 19 ​(inclusively);

Number of times 5 comes = 1

Total number of integers = 20

Similarly, between integer from 0 to 24 ​(inclusively);

Number of times 5 comes = 1

Total number of integers = 25

So, the required probability = \frac{1}{20}\times \frac{1}{25}

                                              = \frac{1}{500} = 0.002

Hence, the probability of selecting 5 both​ times is 0.002.

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Step-by-step explanation:

Domain is all x-values that can be inputted in the graph that returns an output.

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3 years ago
A plan of a garden is shown below.
siniylev [52]

The length and width of the conservatory are both 4.5 meters

<h3>How to determine the length and the width?</h3>

From the figure, we have the following highlights:

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A unit = 1.5 meters

So, we have:

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Width = Length = 4.5 meters

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brainly.com/question/27233632

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1 year ago
Clarence works at least 5 hours but not more than 7 hours. he earns $11.60 per hour. the function f(t)=11.6t represents the amou
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3 years ago
If EF bisects CD.CG = 5x - 1, GD = 7x-13, EF = 6x - 4, and GF = 13. find EG.
Iteru [2.4K]

Answer:

EG = 19

Step-by-step explanation:

* Lets explain how to solve the problem

- If a line bisects another line that means the point of intersection

 divides the second line into two equal parts

∵ EF bisects CD at G

∴ CG = GD

∵ CG = 5x - 1

∵ GD = 7x - 13

∴ 7x - 13 = 5x - 1

* Lets solve the equation

∵ 7x - 13 = 5x - 1

- Subtract 5x from both sides and add 13 to both sides

∴ 7x - 5x = 13 - 1

∴ 2x = 12

- Divide both sides by 2

∴ x = 6

- Point G divides EF into two parts EG and GF

∴ EF = EG + GF

∵ EF = 6x - 4

- Substitute the value of x to find EF

∵ x = 6

∴ EF = 6(6) - 4 = 36 - 4 = 32

∴ EF = 32

∵ GF = 13

- Substitute the values of EF and GF in the equation of EF

∴ 32 = EG + 13

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