The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)
The value of x is 5
<h3>What are algebraic expressions?</h3>
Algebraic expressions are expressions made up;
- Factors
- variables
- terms
- constants
They also consist of mathematical operations such as addition, multiplication, division, subtraction, parenthesis, brackets, etc
We have the expression as;
7.5x = 5.5x + 10
collect like terms
7.5x - 5.5x = 10
subtract the like terms
2.0x = 10
Make 'x' the subject
x = 10/2. 0
x = 5
Thus, the value of x is 5
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