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Anit [1.1K]
3 years ago
10

Lauren save $84 more than Fiona. 1 fifth Of Lauren's saving was the same as 3 eights of fiona's Saving. How much did Lauren and

Fiona save altogether
Mathematics
1 answer:
muminat3 years ago
7 0

Answer:

Lauren's saving=$180

Fiona's saving=$96

Step-by-step explanation:

Let the saving's of fiona be x

Now given that the savings of lauren is $84 more than fiona which means the saving's of lauren is x+84

Given 1 fifth Of Lauren's saving was the same as 3 eights of fiona's Saving

\frac{1}{5}(lauren's saving)=\frac{3}{8}(fiona's saving)

\frac{1}{5}(x+84)=\frac{3}{8}(x)

8x+672=15x

7x=672\\x=96

Therefore the saving's of fiona is $96 and the saving's of Lauren's is 96+84=$180

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Answer:

Step-by-step explanation:

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d) interest is $15, loan period is 2 weeks which occurs once during the loan, interest rate is 10% per two weeks.

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e) P = 15 / 0.10 = $150

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2 years ago
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Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

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c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a \frac{1}{4} = 0.25 probability of getting ir right. So \pi = 0.25. There are five questions, so n = 5.

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There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

P = 0.75(0.25) = 0.1875

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: P = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955

P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637

P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

P = P(X = 3) + P(X = 4) + P(X = 5)

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P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001

P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035

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