50 5/8 divided by 11 1/4
1 answer:
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Answer:
(221.39, 300.61) and (255.2223, 266.7777)
Step-by-step explanation:
Given that X, the lengths of pregnancies in a small rural village are normally distributed with a mean of 261 days and a standard deviation of 17 days
Middle 98% would lie on either side of the mean with probability ±2.33 in the std normal distribution on either side of 0
Corresponding we have x scores as
Between and
i.e. in the interval = (221.39, 300.61)
If sample size = 47, then std error of sample would be
So 98% of pregnancies would lie between
and
= (255.2223, 266.7777)