Hello!
To find the equation of line that passes through (4, 6) and is parallel to y = 3x + 4, we need to use the slope of the given line, and also to find the y-intercept. We use the same slope of the old equation to make the new equation because if two lines are parallel, then their slopes are <u>always equivalent</u> to one another.
To find the equation, we need to use slope-intercept form, which is written as y = mx + b, where m is the slope and b is the y-intercept.
y = 3x + b (substitute the given ordered pair into the equation)
6 = 3(4) + b (simplify - multiply)
6 = 12 + b (subtract 12 from btoh sides)
-6 = b
Therefore, the equation of the line that passes through (4, 6) and is also parallel to y = 3x + 4, is y = 3x - 6.
Answer:
121 – 1 = 120. 120 – 3 = 117.
Step-by-step explanation:
It is a square, so you know the sides are equal. You also know that 49 is a squared number. so you do 49 square rooted and you get 7. the perimeter is adding all the side lengths. So you take 7 and multiply it by 4 since a square has 4 sides. and u have your perimeter. 28!<span />
Since point M is the midpoint of LN, LM and MN are equivalent in length.
7x - 12 = 3x + 16 (LM=MN)
7x = 3x + 28
4x = 28
x = 7
Now that we know the value of x, we can find the value of LM by plugging the value in the equation.
LM = 7(7) - 12
LM = 49 - 12
LM = 37
