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Cloud [144]
3 years ago
14

Find the slope of the line passing through (5,-5) and (8,-8)

Mathematics
1 answer:
LenaWriter [7]3 years ago
3 0
(5,-5)(8,-8)
slope = (-8 - (-5) / (8 - 5) = (-8 + 5) / 3 = -3/3 = -1 <==
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2 years ago
The equations : -3x+4y=-30− and 9x + 5 y = 39 intersect at the coordinate (h, k). What is the value of h?
Phantasy [73]

Answer:

h = 6

Step-by-step explanation:

Given the 2 equations

- 3x + 4y = - 30 → (1)

9x + 5y = 39 → (2)

We require the value of the x- coordinate at the point of intersection, thus require to eliminate the y- term from the equations

Multiply (1) by 5 and (2) by - 4

- 15x + 20y = - 150 → (3)

- 36x - 20y = - 156 → (4)

Add (3) and (4) term by term thus eliminating y

- 51x = - 306 ( divide both sides by - 51 )

x = h = 6

5 0
3 years ago
The coordinates of triangle ABC are A(−4, 3), B(2, 3), and C(4, −1). A line segment runs through the triangle with endpoints Y(0
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We can say that the length of line segment Y'Z' will increase by a scale factor of 2.

4 0
3 years ago
Which of the following equations could be solved for a radius? Select all that apply.
zalisa [80]

Answer:

A = π · (r²)

Step-by-step explanation:

A =π · r² is the area of a circle.

While π · r² · h can also give you the radius, it can only do so for the Volume V, not the Area A.

V=lwh doesn't really apply for a circular object, as it requires the length and width. For circular objects, both are equal to the diameter of the object, and 2² · r² · h does not equal the Volume.

V= π · r³ seems awfully like the volume of a sphere, but there's something missing. The true volume of a sphere is V=\frac{4}{3} · π · r³, not V= π · r³.

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3 0
2 years ago
Read 2 more answers
If JK and LM are congruent and parallel, then JKL and MLK are congruent.
viktelen [127]

Answer:

Given statement is TRUE.

Step-by-step explanation:

Given that line segment JK and LM are parallel. From picture we see that LK is transversal line.

We know that corresponding angles formed by transversal line are congruent.

Hence ∠JKL = ∠ MLK ...(i)

Now consider triangles JKL and MLK

JK = LM  {Given}

∠JKL = ∠ MLK { Using (i) }

KL = KL  {common sides}

Hence by SAS property of congruency of triangles, ΔJKL and ΔMLK are congruent.

Hence given statement is TRUE.

3 0
3 years ago
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