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Komok [63]
3 years ago
12

What is the absolute deviation of 12?

Mathematics
2 answers:
IgorC [24]3 years ago
6 0
The absolute deviation of 12 is 3.75  Absolute deviation is the variability of data.

Your answer is: 3.75 

Have an amazing day!

Minchanka [31]3 years ago
3 0
The mean absolute deviation of a set of data is the average distance between each data value and the mean. The mean number of contacts stored and the distance each data value is from the mean is shown below. Each data value is represented by an ×. So, the mean absolute deviation is 3.75<span>.

</span>
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An English muffin and two fried eggs contain 330 calories. Three English muffins and
nalin [4]

Answer:

m+2e=330

3m+1e=515

use simultaneous formula to get

m=37

e=146.5

3 0
2 years ago
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RUDIKE [14]
C it’s what I chose for it
6 0
2 years ago
Please help me with this question
jek_recluse [69]
A is the correct answer





E is 90 degrees


ABE is 52 so EBD is 64
(180 - 52) \div 2 = 128 \div 2 = 64


so D is 26:
180 - (90 + 64) = 180 - 154  \\  = 126





good luck
3 0
3 years ago
A ship moves through the water at 30 miles/hour at an angle of 30° south of east. The water is moving 5 miles/hour at an angle o
iVinArrow [24]

Answer:

a. 25.98i - 15j mi/h

b. 1.71i + 4.7j mi/h

c. 27.69i -10.3j mi/h

Step-by-step explanation:

a. Identify the ship's vector

Since the ship moves through water at 30 miles per hour at an angle of 30° south of east, which is in the fourth quadrant. So, the x-component of the ship's velocity is v₁ = 30cos30° = 25.98 mi/h and the y-component of the ship's velocity is v₂ = -30sin30° = -15 mi/h

Thus the ship's velocity vector as ship moves through the water v = v₁i + v₂j = 25.98i + (-15)j = 25.98i - 15j mi/h

b. Identify the water current's vector

Also, since the water is moving at 5 miles per hour at an angle of 20° south of east, this implies that it is moving at an angle 90° - 20° = 70° east of north, which is in the first quadrant. So, the x-component of the water's velocity is v₃ = 5cos70° = 1.71 mi/h and the y-component of the water's velocity is v₄ = 5sin70° = 4.7 mi/h

Thus the ship's velocity vector v' = v₃i + v₄j = 1.71i + 4.7j mi/h

c. Identify the vector representing the ship's actual motion.

The velocity vector representing the ship's actual motion is V = velocity vector of ship as ship moves through water + velocity vector of water current.

V = v + v'

= 25.98i - 15j mi/h + 1.71i + 4.7j mi/h

= (25.98i + 1.71i + 4.7j - 15j )mi/h

= 27.68i -10.3j mi/h

7 0
3 years ago
What is The answer to this equation -9•(5j+k)
vlada-n [284]

Answer:

-45j -9k

Step-by-step explanation:

5 0
3 years ago
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