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Ronch [10]
3 years ago
13

PLEASE HELP! URGENT! Exponential function f is being represented by the table (photo attached) the function “g” is an exponentia

l function passing through the points of (0, 15) , (2, 0). Which of the statements below correctly compared the behavior of these two functions on the interval (0, 2) ??

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
6 0

Answer:

C) Both functions are decreasing and both are positive on the interval (0;2)

Step-by-step explanation:

As known the exponent function has no minimum and has no maximum.

Otherwise exponent function can be only or increasing or decreasing for all x.

That means that in case y(x2)>y(x1) and  if x2>x1-  function is increasing.

That means that in case y(x2)<y(x1) and  if x2>x1-  function is decreasing.  

Lets check what is going on with the function f(x)

If x1=0        f(x1)=24

If x2=2        f(x2)=0

So    x2>x1 however f(x2)<f(x1)=> function is decreasing

Similarly g(x)

If x1=0   g(x1)=15

If x2=2   g(x2)=0

So x2>x1 however g(x2)<g(x1) => function is decreasing

So bothfunctions are decreasing.

Because f(x) is decreasing the function meaning with argument x1=0 has max in the interval x∈(0;2) And function meaning has the minimum if argument x2=2.   So the function F(x) in interval (0;2) is changing from 24 to 0 => is positive on the interval (0,2)

The same is with g(x) .  g(x) gonna be positive on the interval (0;2)

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if a sequence is defined recursively by f(0)=4 and f(n+1)= -3f(n+1)=-3f(n)+1 for n≥0, then f(3) is equal to? DESPERATELY NEED HE
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<u>Step-by-step explanation</u>:

  • The sequence is followed by f(0)=4
  • The given expression is f(n+1)= -3f(n)+1

Put n=0,

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