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puteri [66]
3 years ago
11

3(2y-3)=27 what is my answer

Mathematics
2 answers:
Liula [17]3 years ago
8 0
Step one- distribute
6y-9=27
Step 2- subtract 9 on both sides
6y=18
Step 3 divide on both sides
Y=3
nydimaria [60]3 years ago
6 0

Answer:

y= 6

Step-by-step explanation:

3 (2y-3) =24

3x2y =6y

3x (-3)= -9

6y -9 =24

    +9 on both sides

6y = 24+9

6y= 36

Divide each side by 6

y= 6

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Maria throws a softball straight up into the air with an initial velocity of 50 ft/sec. The ball leaves her hand when it is exac
Nataly_w [17]

Answer:

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

Step-by-step explanation:

Let suppose that effects from air friction and Earth's rotation can be neglected, so that the softball can be modelled experiment a free fall, that is, an uniform accelerated motion due to gravity. From we know the initial velocity and position of the position and we can determine the final position of the ball as a function of the final velocity:

v_{f}^{2} = v_{o}^{2}+2\cdot a \cdot (s_{f}-s_{o}) (1)

Where:

s_{o}, s_{f} - Initial and final position of the softball, measured in feet.

a - Acceleration, measured in meters per square second.

v_{o}, v_{f} - Initial and final velocities of the softball, measured in feet per second.

If we know that v_{o} = 50\,\frac{ft}{s}, a = -32.174\,\frac{m}{s^{2}} and s_{o} = 4\,ft, then the equation that models the situation is:

v_{f}^{2} = 2500-64.348\cdot (s_{f}-4)

Then, we clear the final position of the softball:

-\frac{v_{f}^{2}-2500}{-64.348} = s_{f}-4

s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}

The equation that models the situation is s_{f} = 4+\frac{v_{f}^{2}-2500}{64.348}.

8 0
2 years ago
HELPPPPPPPPPPPPPPPPP
igomit [66]
X=3
LOM and KOL are equivalent, so the equation is 43=6x+25 :)
5 0
2 years ago
Consider the following functions
TiliK225 [7]

Step-by-step explanation:

g(5)=3(5)-11

=15-11

=4

f(g(5))=2(4)²+4(4)+10

=2(16)+16+10

=32+26

=58

5 0
3 years ago
Strontium-90 has a half-life of 28.8 years. If you start with a 300-gram sample of strontium-90,
Kazeer [188]

Answer:  2.66 × 10⁻¹³

<u>Step-by-step explanation:</u>

First, use the decay formula   A=A_oe^{kt}   where

  • A is the final amount (amount left)
  • A₀ is the initial amount (amount you started with)
  • k is the rate of decay (you need to solve for this)
  • t is the time

Given:

  • A = 1/2(300) = 150
  • A₀ = 300
  • k = unknown
  • t = 28.8

150=300e^{28.8k}\\\\0.5=e^{28.8k}\\\\ln(0.5)=ln(e^{28.8k})\\\\ln(0.5)=28.8k\\\\\\\dfrac{ln(0.5)}{28.8}=k\\\\\\\large\boxed{-0.0240676=k}\\

Next, input the k-value and the new t-value to solve for A.

  • A = unknown
  • A₀ = 300
  • k = -0.0240676
  • t = 1440

A=300e^{1440(-.0240676)}\\\\\large\boxed{A=2.66\times 10^{-13}}\\

5 0
3 years ago
Is √8 a rational number ?
bonufazy [111]
Yeah I’m pretty sure it is a rational number
4 0
2 years ago
Read 2 more answers
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