Answer:
Indirect variation
Step-by-step explanation:
If two variables change in inverse proportion, then it is called indirect variation.
xy = k where k is a constant.
5*2 = 10
10*1 =10
![15*\dfrac{2}{3}=5*2=10\\\\\\20*\dfrac{1}{2}=10](https://tex.z-dn.net/?f=15%2A%5Cdfrac%7B2%7D%7B3%7D%3D5%2A2%3D10%5C%5C%5C%5C%5C%5C20%2A%5Cdfrac%7B1%7D%7B2%7D%3D10)
So, this is indirect variation.
Answer:
125
Step-by-step explanation:
125 ÷ 3 = 41 2/3 so 125 is not divisible by 3
Its true, 2 kilos = 4 pounds
Answer:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): ![\mu \geq 2000](https://tex.z-dn.net/?f=%5Cmu%20%5Cgeq%202000)
Alternative hypothesis (H1): ![\mu](https://tex.z-dn.net/?f=%5Cmu%20%3C2000)
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 200 or no
Step-by-step explanation:
For this case we want to test if the the average monthly income of all students at college is at least $2000. Since the alternative hypothesis can't have an equal sign thne the correct system of hypothesis for this case are:
Null hypothesis (H0): ![\mu \geq 2000](https://tex.z-dn.net/?f=%5Cmu%20%5Cgeq%202000)
Alternative hypothesis (H1): ![\mu](https://tex.z-dn.net/?f=%5Cmu%20%3C2000)
And in order to test this hypothesis we can use a one sample t or z test in order to verify if the true mean is at least 2000 or no
Answer: p = 6
Step-by-step explanation:
HI !
px + 3y - ( p-3)=0
a₁ = p , b₁ = 3 , c₁ = - (p-3)
=====================
12x + py - p=0
a₂ = 12 , b₂ = p , c₂ = -p
since , the equations have infinite solutions ,
a₁/a₂ = b₁/b₂ = c₁/c₂
p/12 = 3/p = p-3/p
--------------------------------------
p/12 = 3/p
cross multiply ,
p² = 36
p = √36
p = 6
for the value of p = 6 , the equations will have infinitely many solutions