Answer:
x > 8
Step-by-step explanation:
I hope this helps you out!
Cone details:
Sphere details:
================
From the endpoints (EO, UO) of the circle to the center of the circle (O), the radius is will be always the same.
<u>Using Pythagoras Theorem</u>
(a)
TO² + TU² = OU²
(h-10)² + r² = 10² [insert values]
r² = 10² - (h-10)² [change sides]
r² = 100 - (h² -20h + 100) [expand]
r² = 100 - h² + 20h -100 [simplify]
r² = 20h - h² [shown]
r = √20h - h² ["r" in terms of "h"]
(b)
volume of cone = 1/3 * π * r² * h
===========================




To find maximum/minimum, we have to find first derivative.
(c)
<u>First derivative</u>

<u>apply chain rule</u>

<u>Equate the first derivative to zero, that is V'(x) = 0</u>




<u />
<u>maximum volume:</u> <u>when h = 40/3</u>


<u>minimum volume:</u> <u>when h = 0</u>


Answer: 21
Step-by-step explanation:
Ok so first of all the numbers in the parentheses go first.
So 6 to the power of 2 (6^2) would be 6x6 which equals 36
50-36=14
After that you just keep rewriting the problem after every step.
Since the 3 is outside of the parentheses, you would multiply it with the 14
3x14=42
Finally 42÷ 2=21
3x (50 - 6^2) ÷ 2 =
3(14)÷ 2
42÷ 2= <u><em>21</em></u>
<u><em></em></u>
<u><em></em></u>
<u><em>Hope this helps (:</em></u>
<u><em>Btw sorry if it's a bit confusing but the answer is 21</em></u>
Answer:
£342,000
Step-by-step explanation:
190,000 x 1.8=342,000
for 1 year
Answer: 15
Step-by-step explanation:
x 60
___ = ____
24 100
15