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Ne4ueva [31]
3 years ago
7

For the function {(0,1), (1,-3), (2,-4), (-4,1)}, write the domain and range.

Mathematics
2 answers:
lukranit [14]3 years ago
6 0

Answer:

B.

D. [-4, 0, 1, 2]

R. [-4, -3, 1]

shepuryov [24]3 years ago
4 0

Answer:

pretty sure it's B

Step-by-step explanation:

domain is x numbers and that has all the x numbers in it

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Step-by-step explanation:

We need to think backwards to solve this question.

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Use the identity (x^2+y^2)^2=(x^2−y^2)^2+(2xy)^2 to determine the sum of the squares of two numbers if the difference of the squ
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Answer:

Step-by-step explanation:

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2

Adding and substracting 2x^2y^2

We get

(x^2+y^2)^2=(x^2)^2+2x^2y^2+(y^2)^2 +2x^2y^2-2x^2y^2

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Moreever we know (a·b·c)^2=a^2·b^2·c^2 than means 2^2x^2y^2=(2x·y)^2

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Rzqust [24]

Answer:

<u>Given function</u>

  • h(x) = 2x - 1

#15 Find the inverse of h(x)

<u>Substitute x with y and h(x) with x and solve for y:</u>

  • x = 2y - 1
  • 2y = x + 1
  • y = 1/2x + 1/2

<u>The inverse is:</u>

  • h⁻¹(x) = 1/2x + 1/2

#16 The graph with both lines is attached.

The x- and y-intercepts of both functions have reversed values.

#17 Table of the inverse function  will contain same numbers with swapped domain and range.

<u>Initial look is like this:</u>

  • <u>x        |  -3  |  -2  | -1  |  0  |    1  |  2  | 3</u>
  • h⁻¹(x)  |  -1   |       | 0   |      |    1  |      | 2

<u>The rest of the table is filled in by finding the values:</u>

  • <u>x        |  -3  |  -2    | -1  |  0   |  1  |  2   | 3</u>
  • h⁻¹(x)  |  -1   | -0.5 |  0  | 0.5 |  1  | 1.5 | 2

7 0
3 years ago
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Answer:

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3 years ago
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