The area shaded in green is 864 cm²
<h3>Similar figures</h3>
Similar figures, corresponding angles are congruent and the sides are ratio of each other. Therefore,
AB / PQ = CD / RS
30 / 10 = 24 / RS
30RS = 240
RS = 240 / 30
RS = 8 cm
let find the height of trapezium PQRS.
AB / PQ = 36 / h
30 / 10 = 36 / h
30h = 360
h = 360 / 30
h = 12 cm
Therefore,
area of the green portion = area of ABCD - area of PQRS
<h3>Area of a trapezium</h3>
Therefore,
area of ABCD = 1 / 2(24 + 30)36 = 1 / 2 (54)36 = 1944 / 2 = 972 cm²
area of PQRS = 1 / 2(10 + 8)12 = 1 / 2(18)12 = 216 / 2 = 108 cm²
Area of the green portion = 972 - 108 = 864 cm²
learn more on trapezium here: brainly.com/question/11961445
A^2 + 31 = 155 - I squared each of b and c for those numbers
a^2 = 155 - 31
a^2 = 124
a = 4 * sqrt(31)
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Answer:
26, 37, 40, 48
Step-by-step explanation:
Whole numbers between 20 and 50 will have 10s digits in the range 2–5.
When 4 is added to these numbers, we get ...
2+4 = 6
3+4 = 7
4+4 = 8
5+4 = 9
When 4 is subtracted from these numbers, we get ...
2-4 = -2
3 -4 = -1
4 -4 = 0
5 -4 = 1
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The numbers we can make using the given 10s digits and their corresponding 1s digit(s) are ...
26, 37, 40, 48
__
We note that any number with a 10s digit of 5 and a 1s digit other than 0 will be out of range.
I honestly don’t know I just need points k thanks bye
Answer:
-5120
Step-by-step explanation:
a = 10
r = -2
Tenth term: 10(-2)⁹
= -5120