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2 years ago

A function is shown on the graph what is the domain of the function?

Mathematics

2 answers:

Ronch [10]2 years ago

6 0

Answer:

you need to add the graph

sladkih [1.3K]2 years ago

4 0

Answer:

no graf

Step-by-step explanation:

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CAN SOMEONE PLEASE HELP ME???

AleksandrR [38]

Answer: The answer is 5.6d+ 2.1

Step-by-step explanation:

Add then subtract then add then multiply then subtract then divide.

5 0

2 years ago

Read 2 more answers

-/2 points

Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval (-∞,∞)

Part 2) The range is the interval (-∞,1]

Step-by-step explanation:

we have

$f(x)=-x^2+14x-48$

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

The range is the interval

(-∞,k]

Find the vertex

$f(x)=-x^2+14x-48$

Factor -1 the leading coefficient

$f(x)=-(x^2-14x)-48$

Complete the square

$f(x)=-(x^2-14x+49)-48+49$

$f(x)=-(x^2-14x+49)+1$

Rewrite as perfect squares

$f(x)=-(x-7)^2+1$

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0

3 years ago

If g(x) = 2x + 3 and f(x) = x<br><br>2 − 49x, find all solutions of the equation f(g(x)) = 0.

sdas [7]

Basically you just have to plug in g(x) wherever you see an x in the equation f(x) since x is f(x) you just substitute it . So f(g(x))=2x+3

You then just have to solve for 0

0=2x+3
Subtract 3 from both sides
-3=2x
Divide by 2
X=-3/2

4 0

3 years ago

He wants to earn 481$ By mowing lawns and he charge $22 for each long what is the maximum number of lungs that he needs to mow t

Reika [66]

$\stackrel{\stackrel{total~amount}{goal}}{481}~~ = ~~22(lawn)\implies \cfrac{481}{22}=lawn\implies \stackrel{rounded}{22}\approx lawn$

6 0

1 year ago

V150<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B150%20%7D%20%20%5C%5C%20" id="TexFormula1" title=" \sqrt{150 } \\ " alt=

Anuta_ua [19.1K]

Answer: 12.2474487139

Step-by-step explanation:

(I think what you wrote is just the square root of 150? if I read this wrong please let me know so I can correct my answer.)

*If you plug in the square root of 150 into a calculator, you get 12.2474487139

6 0

2 years ago