The correct answer is that 1.125 mol of NaOH is available, and 60.75 g of FeCl₃ can be consumed.
The mass of NaOH is 45 g
The molar mass of NaOH = 40 g/mol
The moles of NaOH = mass / molar mass
= 45 / 40
= 1.125
Thus, 1.125 mol NaOH is available
3 NaOH + FeCl₃ ⇒ Fe (OH)₃ + 3NaCl
3 mol of NaOH react with 1 mol of FeCl₃
1.125 moles of NaOH will react with x moles of FeCl₃
x = 1.125 / 3
x = 0.375 mol
0.375 mol FeCl₃ can take part in reaction
The molar mass of FeCl₃ is 162 g/mol
The mass of FeCl₃ = moles × mass
= 0.375 × 162
= 60.75 g
Thus, the amount of FeCl₃, which can be consumed is 60.75 g
The entire woodpecker population would be DESTROYED
Answer:
1. More data should be collected to get a more reliable average
2. A boiling point at 1.5 atmospheres could be predicted fairly well
3. The actual boiling point is probably between 34 C and 40 C
4. By taking 10 measurements of each of the five liquids and finding an average
5. The thermometer being used might need to be recalibrated
Explanation:
Took the quick check
The equation MgO + 2HCl → MgCl₂ + H₂O is a balanced equation.
- A balanced chemical equation contains equal number of atoms on both sides of the equation.
- The equation is MgO + 2HCl → MgCl₂ + H₂O which contains 1 atom of Mg, 2 atoms of chlorine, 2 atoms of chlorine, 1 atom of oxygen on both reactants and products sides.
- So the equation is balanced.
- An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and total charge for each component of the reaction.
- In other words, both sides of the reaction have equal amounts of mass and charge.
- It follows law of conservation of mass.
- Mass is neither created nor destroyed rather it can be transferred from one form to another.
Learn more about balanced equation at:
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The uranium within these items is radioactive and should be treated with care. Uranium's most stable isotope, uranium-238, has a half-life of about 4,468,000,000 years. It decays into thorium-234 through alpha decay or decays through spontaneous fission.
