A galvanic cell is formed when two metals are immersed in solutions differing in concentration 1 when two different metals are immersed.
<h3>What is galvanic cell?</h3>
A galvanic cell is an electrochemical device that transforms chemically generated free energy into electrical energy. A photogalvanic cell produces photochemical species that react to produce an electrical current when connected to an external circuit.
<h3>How does galvanic cell works?</h3>
In order to create a pathway for the flow of electrons via this wire, the galvanic cell makes use of the ability to split the flow of electrons during the processes of oxidation and reduction, forcing a half-reaction and linking each with a wire.
An electrochemical device known as a galvanic cell converts chemical energy from a spontaneous redox response into electrical energy. It possesses an electrical potential of 1.1 V. The anode, which is a negative plate in galvanic cells, is where oxidation takes place. It is a positive plate where lessening takes place.
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The molecule with higher dipole moment is COFH because the geometry of the molecule in the COF2 nearly cancel the dipolar moment of each other. To be more clear:
The dipolar moment is the vectorial sum of all bond moments in the molecule or dipolar moment of each bond. The dipolar moment of a molecule with three or more atoms is determined by bond polarity as their geometry.
COF2 has a trigonal planar structure which are symmetric. The electronegativity of oxygen is slightly different regarding fluor. So as you can see in the image, the electronic density is specially displaced to the fluor atoms, but either to the oxygen atom.
COFH has a trigonal structure but differs from COF2 because there is an hydrogen who is donating it's electronic density, so in this zone the electronic density is less than over oxygen or fluor. That makes bond angles be different between them.
Elements in the third row can break the octet rule
Answer:
6.43 moles of NF₃.
Explanation:
The balanced equation for the reaction is given below:
N₂ + 3F₂ —> 2NF₃
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Finally, we shall determine the number of mole of nitrogen trifluoride (NF₃) produced by the reaction of 9.65 moles of Fluorine gas (F₂). This can be obtained as follow:
From the balanced equation above,
3 moles of F₂ reacted to produce 2 moles of NF₃.
Therefore, 9.65 moles of F₂ will react to to produce = (9.65 × 2)/3 = 6.43 moles of NF₃.
Thus, 6.43 moles of NF₃ were obtained from the reaction.
