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Ivanshal [37]
4 years ago
10

A student visits the beach during a very hot day. She steps on the sand and jumps because it is so hot. What type of heat transf

er is demonstrated by the sand in this example?
Chemistry
2 answers:
Vlad [161]4 years ago
7 0

Answer: Conduction, because her feet are touching the hot sand.

sammy [17]4 years ago
3 0
Answer is: thermal conductuction.
Thermal conductuction is the transfer of heat<span> through physical contact. </span>Thermal conduction<span> is the transfer of heat</span> by microscopic collisions of particles. <span>Heat spontaneously flows from a hotter to a colder body.
</span>The process of heat conduction depends on four basic factors: the temperature gradient<span>, the cross section of the </span>materials<span> involved, their path length and the properties of those materials.</span>


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Negative radical in the periodic table​
yKpoI14uk [10]

Answer:

A radical is a group of atoms of elements carrying a charge, e.g., chlorate [ClO3–]. Radicals or ions are formed by losing or gaining electrons. When an electron is gained the group of atoms acquire a negative charge and is called a negative radical or negative ion.

5 0
3 years ago
first used the term cell when he used a (5)_____ to observe box-like structures when he was examining cork under a microscope. (
MrRa [10]

Answer:

sorry if its wrong.

Explanation:

(5) a cell was used to refer to these tiny units of life

(6) Robert Hooke

(7)  cell walls

(8) modern cell theory. im so sorry if im wrong.

3 0
3 years ago
Copper can have improved wear resistance if alloyed with ceramic alumina, Al2O3. If a copper alloy has 7.7 wt % Al2O3, what is i
vitfil [10]

The composition in mol% of the elements are :

  • 4.91%  of Al₂O₃ in alloy  
  • 95.08% of Cu in alloy

<u>Given data : </u>

Weight percentage of copper alloy = 7.7 wt %

Assume weight of alloy = 100 grams

<h3>Applying the weight percentage </h3>

mass of Al₂O₃ in alloy = 7.7 gm

Mass of Cu in alloy = 100 - 7.7 = 92.3 gm

<u />

<u>First step : calculate the mole of elements</u>

i) moles of Al₂O₃ in alloy

 = mass of Al₂O₃  in alloy /  Atomic mass of Al₂O₃

 = 7.7 gm  / 102 gm/mol

 = 0.075 mol

ii) moles of Cu in alloy

 = mass of Cu in alloy / Atomic mass of Cu

 = 92.3 gm / 63.5 gm/mol

 = 1.45 mol

Therefore the total number of moles in the alloy = 0.075 + 1.45 = 1.525

<u>Next step : Determine the mole </u><u>percentages </u>

i) Mole percentage of Al₂O₃ in alloy  

= ( 0.075 ) / 1.525  * 100

= 4.91%

ii) Mole percentage of Cu in alloy

= ( 1.45 ) / 1.525 * 100

= 95.08%

<u />

Hence we can conclude that The composition in mol% of the elements are : 4.91%  of Al₂O₃ in alloy and  95.08% of Cu in alloy.

Learn more about alloys : brainly.com/question/716507

4 0
3 years ago
Hclo is a weak acid (ka = 4.0 × 10–8) and so the salt naclo acts as a weak base. what is the ph of a solution that is 0.089 m in
Anuta_ua [19.1K]

Answer: 14

Explanation:

6 0
3 years ago
How many moles of MgS2O3 are in 173 g of the compound?
liq [111]
There are 1.27 moles in the compound.


4 0
3 years ago
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