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2 years ago

Is it right And why

Mathematics

1 answer:

antiseptic1488 [7]2 years ago

7 0

Yes it is indeed correct,
B. 7.47 is the correct answer!
Brainliest pls! thx! :)

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Tell whether the triangles are similar.

Vilka [71]

Answer: I think it’s not similar becaus of the size.

It’s also a different number so it’s a no.

Step-by-step explanation:

4 0

2 years ago

Find the equation of the line passing<br> through the points (3,-2) and (4, 6).<br> y = 8x + [?]

Sauron [17]

Step-by-step explanation:

1.) Plug in one of the points.

y = 8x + b

6 = 8(4) + b

2.) Solve for b (or [?])

$6 = 32 + b \\ - 32 \: \: \: \: \: \: \: \: \: - 32$

32 cancels out on the right side.

Subtract 32 from 6, which is -26

3.) -26 = b

4.) Check with other point:

-2 = 8(3) + b

-2 = 24 + b

Cancel out 24 on the right side: 24-24 = 0

-2 - 24 = -26

-26 = b

4 0

2 years ago

Which inequality can be used to represent a number x that is less than equal to 8 and greater than -3

KIM [24]

Answer: x = -2,-1, 0, 1, 2, 3, 4, 5, 6, 7, 8

Solution:

A number line is used to represent the possible numbers that x can be.

x that is less than equal to 8 >>>> x ≤ 8

x is greater than -3 >>>> x > -3

So it will be represented as,

-3 < x ≤ 8

So all the numbers between -3 and 8 including eight (because it has the equal sign)

-2,-1, 0, 1, 2, 3, 4, 5, 6, 7, 8

7 0

2 years ago

Solve 10e^2x - 5 =23^x for x.

yawa3891 [41]

$10e^{2x}-5=23e^x\qquad\text{subtract}\ 23e^x\ \text{from both sides}\\\\10e^{2x}-23e^x-5=0\\\\10(e^x)^2-23(e^x)-5=0\\\\\text{substitution:}\ e^x=t > 0\\\\10t^2-23t-5=0\\\\10t^2-25t+2t-5=0\\\\5t(2t-5)+1(2t-5)=0\\\\(2t-5)(5t+1)=0\iff2t-5=0\ \vee\ 5t+1=0\\\\2t=5\ \vee\ 5t=-1\\\\t=\dfrac{5}{2} > 0\ \vee\ t=-\dfrac{1}{5} < 0\\\\\text{therefore}\ e^x=\dfrac{5}{2}\to\ln e^x=\ln\left(\dfrac{5}{2}\right)\\\\\boxed{x=\ln\left(\dfrac{5}{2}\right)}$

5 0

2 years ago

Read 2 more answers

KLMN is a parallelogram,

Aleonysh [2.5K]

Answer:

Ok soo.

Step-by-step explanation:

sum of two adjacent angles of parallelogram is 180

so angle K + angle L = 180

as AK bisects angle K and LA bisects angle L

so, angle AKL + angle ALK = 180 /2 = 90

in triangle AKL,

angle AKL + angle ALK+angle KAL = 180(sum of all angles in triangle = 180)

so, from above two equations,

angle KAL = 90

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4 0

2 years ago