Answer:
The annual growth rate between 1985 and 2005 is 0.95%
The value of the house in the year 2010 is $152,018
Step-by-step explanation:
Let the annual growth rate = r
Value of the house in year 1985 = $120,000
Value of the house in year 2005 = $145,000
Time (t) = 2005 - 1985
= 20 years
A = P (1 + r)^t
145000 = 120000 (1 + r) ^20
(1 +r)^20 = 145000 / 120000
(1 +r)^20= 1.2083
(1 +r)^20= (1.2083)^1/20
(1 +r)^20= 1.0095
r = 1.0095 - 1
r = 0.0095
r% = 0.0095 x 100
= 0.95%
Value of the house in year 2010
=145000(1 + r)^5
=145000 (1 + 0.0095)^5
= 145000 x 1.0484
=$152,018
Answer:
f(10) = - 26
Step-by-step explanation:
To evaluate f(10), substitute x = 10 into f(x), that is
f(10) = 4 - 3(10) = 4 - 30 = - 26
3(2t+5)=5t+25
Multiply the bracket with 3
(3)(2t)(3)(5)=5t+25
6t+15=5t+25
Move 5t to the other side. Sign changes from +5t to -5t
6t-5t+15=5t-5t+25
6t-5t+15=25
Move +15 to the other side. Sign changes from +15 to -15
6t-5t+15-15=25-15
6t-5t=10
1t=10
divide by 1
1/1t=10/t
t=10
Answer: t=10
Answer:
1a
2b
3a
4c
5c
6c
7a
8d
9b
10b
11a
12c
13b
14a
15a
Step-by-step explanation:
Answer:
A. can I come anwser my question
