The solution to the given compound inequality 2x - 3 < x + 2 ≤ 3x + 5 is 5 > x ≥ -3/2
<h3>Compound inequality</h3>
2x - 3 < x + 2 ≤ 3x + 5
solve differently
2x - 3 < x + 2
2x - x < 2 + 3
x < 5
x + 2 ≤ 3x + 5
x - 3x ≤ 5 - 2
-2x ≤ 3
x ≥ 3/-2
x ≥ -3/2
Therefore, the solution of the compound inequality is 5 > x ≥ -3/2
Learn more about compound inequality:
brainly.com/question/234674
#SPJ1
Answer:
64?
Step-by-step explanation:
I think so...I'm not sure
Answer:
55f + 45
Step-by-step explanation:
5 (11f +9)
5 times 11f, then 5 times 9
55f + 45 -> since the 9 was positive we add!
I hope this helps you!
Answer:
a) DF = 20
b) DF =
Radical Form = sqrt(53)
Decimal Form = 7.28
