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vekshin1
3 years ago
5

For each ordered pair, determine whether it is a solution to 7x+3y=2

Mathematics
1 answer:
Lapatulllka [165]3 years ago
5 0

Answer:

Step-by-step explanation: i thimk 5,2

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2a - 4b +3ab -5a +2b
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-3a-2b+3ab

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2a-5a

-4b+2b

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According to a medical study, 15% of people will experience an adverse side effect
ahrayia [7]

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c

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iren2701 [21]

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company A pays more, by the end of yr 10 they pay $9000 more

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6 0
3 years ago
N aumentado en un 25%
Shkiper50 [21]

Answer:

1.25 * N

Step-by-step explanation:

We have to increase N by 25%.

The first thing is to say how the percentage works in these cases, N would be our 100% and the increase would be 25% in this case, therefore, the initial value must be added (that is, N, 100%) and to that if add 25% of the initial value (that is, + 25% N).

Thus:

100% * N + 25% * N = N * (100% + 25%)

N * (125%) = 1.25 * N

So to increase N is 25% it would be 1.25 * N

8 0
3 years ago
the sum of the two trains is 723.5 mph if the speed of the first train is 12.5 mph faster than that of the second train find the
jonny [76]
First, let's see if we can rewrite this word problem a little bit more mathematically. We won't get to mathy or technical so no worries. We just want to look at it in a more straightforward way, if we can.

Train A's mph plus Train B's mph summed equal 723.5 mph. Train A's mph is greater than Train B's mph by 12.5 mph.   
So what should we do to solve this problem? Since we are dealing with two of something and we know the value of the two combined, it might make sense to start by dividing that value by 2.
723.5 / 2 = <em /> 361.75. If the two trains were travelling at the same speed, we would be done. Unfortunately, they are not so we need to think about this some more. 
Train A is going 12.5 mph faster than Train B. Let's rewrite.
Train A mph = 12.5 + 361.75 = 374.25  Okay, so Train A is travelling at a speed of 374.25 mph. So we're done right? Not exactly. We are asked to fing the speeds of BOTH trains. How do we find the speed of Train B? We have added a portion of the combined total to Train A. It seems to follow, then, we should probably subtract the same portion from Train A. What are we going to do? You guessed it! Rewrite.
Train B mph = 361.75 - 12.5 = 349.25 HA HA! We seem to have figured it out. Let's do one last thing to check our work. Let's add the two trains' speeds together. If we did this right, we should get our summed value of 723.5 mph
374.25 + 349.25 = 723.5
Pat yourself on the back! We did it!

374.25 + 349.25 =

3 0
3 years ago
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