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juin [17]
3 years ago
8

im just wondering if any of you guys have school bc todays election day and their a bunch of questions

Mathematics
2 answers:
schepotkina [342]3 years ago
6 0

Answer:

I have school yessir

Step-by-step explanation:

bagirrra123 [75]3 years ago
3 0

Answer:

i do have school today

Step-by-step explanation:

hope you have a good day though :)

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Solve this question :<br> -10k2+7
german

Answer:

-10k×2+7

= -20k+7

Step-by-step explanation:

is the answer

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An Aluminum bar is 2 m long at a temperature of 20 degrees Celsius. What will it be at 100 degrees Celsius?
ddd [48]

Answer:

5

Step-by-step explanation:

20*5=100

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Annie is framing a photo with a length of 6 inches and a width of 4 inches. The distance from the edge of the photo to the edge
Ede4ka [16]

Answer:

Part a) The quadratic function is 4x^{2} +20x-39=0

Part b) The value of x is 1.5\ in

Part c) The photo and frame together are 7\ in wide

Step-by-step explanation:

Part a) Write a quadratic function to find the distance from the edge of the photo to the edge of the frame

Let

x----> the distance from the edge of the photo to the edge of the frame

we know that

(6+2x)(4+2x)=63\\24+12x+8x+4x^{2}=63\\ 4x^{2} +20x+24-63=0\\4x^{2} +20x-39=0

Part b) What is the value of x?

Solve the quadratic equation 4x^{2} +20x-39=0

The formula to solve a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}

in this problem

we have

4x^{2} +20x-39=0

so

a=4\\b=20\\c=-39

substitute in the formula

x=\frac{-20(+/-)\sqrt{20^{2}-4(4)(-39)}} {2(4)}

x=\frac{-20(+/-)\sqrt{1,024}} {8}

x=\frac{-20(+/-)32} {8}

x=\frac{-20(+)32} {8}=1.5\ in  -----> the solution

x=\frac{-20(-)32} {8}=-6.5\ in

Part c) How wide are the photo and frame together?

(4+2x)=4+2(1.5)=7\ in

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3 years ago
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Dvinal [7]

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