Answer:
Answer: The missing value is 4.5 or 9/2.
Answer:
40 days saw either rain or high winds
Step-by-step explanation:
We solve this question using Venn sets.
I am going to say that:
Set A: Rain
Set B: High winds.
18 days saw rain
This means that ![A = 18](https://tex.z-dn.net/?f=A%20%3D%2018)
29 days saw high winds
This means that ![B = 29](https://tex.z-dn.net/?f=B%20%3D%2029)
7 days saw both rain and high winds.
This means that ![A \cap B = 7](https://tex.z-dn.net/?f=A%20%5Ccap%20B%20%3D%207)
How many days saw either rain or high winds?
This is
![A \cup B = A + B - A \cap B](https://tex.z-dn.net/?f=A%20%5Ccup%20B%20%3D%20A%20%2B%20B%20-%20A%20%5Ccap%20B)
Sp
![A \cup B = 18 + 29 - 7 = 40](https://tex.z-dn.net/?f=A%20%5Ccup%20B%20%3D%2018%20%2B%2029%20-%207%20%3D%2040)
40 days saw either rain or high winds
Answer:
Step-by-step explanation:
The gradient is the the slope of the equation.
5x - 2y = 12
Making y as subject of formula
2y = 5x - 12
Dividing through by 2
y = 5x/2 - 12/2
y = 5x/2 - 6
And comparing with y = mx + c
Where m is the slope = 5/2
By the remainder theorem the remainder when dividing p(x) by x-a is p(a).
Dividing by x+1 means we want p(-1).
p(-1) = (-1)³ - 2(-1)² -4(-1) - 1 = -1 - 2 + 4 - 1 = 0
Answer: 0
They go in evenly so x+1 is a factor of p(x).