Answer:
Variant c
Step-by-step explanation:
c²=4*9
c=6
You can apply phyphagor
b²=6²+9²=36+81=117

Answer:
6a^2+ 2bc-2c^1/3 <u>= 162</u>
Step-by-step explanation:


![\rm = 6 + 162 - 2 ( \sqrt[3]{27} )](https://tex.z-dn.net/?f=%20%5Crm%20%20%3D%206%20%2B%20162%20-%202%20%28%20%5Csqrt%5B3%5D%7B27%7D%20%29)



Answer:
119.05°
Step-by-step explanation:
In general, the angle is given by ...
θ = arctan(y/x)
Here, that becomes ...
θ = arctan(9/-5) ≈ 119.05°
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<em>Comment on using a calculator</em>
If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.
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It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...
Tan = Opposite/Adjacent = |y|/|x|
This is the tangent of the reference angle, which will be ...
θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°
You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.
Just by looking at 14 it will be non linear since any equation that has an exponent will automatically be non linear and will not form a straight line. 13 would be linear as when you subtract x from both sides you’ll have a straight line meaning it’s linear. And 12 will be linear because the equation once into y=mx+b format it will be y=-2x/3+7/3 making a straight line if graphed correctly.