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ruslelena [56]
3 years ago
7

Classify each scale factor as a contraction or an expansion. 3/2, 1/3, 4, 2/5, 4/3, 1/4.

Mathematics
1 answer:
DaniilM [7]3 years ago
8 0
The question is asking to state if those following scale factors are consider as contraction or expansion, base on my research and further analysis, the possible answer are the following:
3/2 expansion
1/3 contraction
4 contraction
2/5 contraction
4/3 expansion
1/4 contraction

I hope you are satisfied with my answer and feel free to ask for more if you have question and further clarifications 
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Look at the triangles shown below.
Sophie [7]

Answer:

Variant c

Step-by-step explanation:

c²=4*9

c=6

You can apply phyphagor

b²=6²+9²=36+81=117

3 \sqrt{13}

4 0
3 years ago
What is the ratio between the LCM of 180 and 594 and the GCF of 180 and 594
aalyn [17]

180:2=90\\90:2=45\\45:3=15\\15:3=5\\5:5=1\\\\180=\boxed{2}\cdot2\cdot\boxed{3}\cdot\boxed{3}\cdot5\\\\594:2=297\\297:3=99\\99:3=3\\33:3=11\\11:11=1\\\\594=\boxed{2}\cdot\boxed{3}\cdot\boxed{3}\cdot3\cdot11

LCM(180,\ 594)=\boxed{2}\cdot\boxed{3}\cdot\boxed{3}\cdot2\cdot3\cdot5\cdot11=5940\\\\GCF(180,\ 594)=\boxed{2}\cdot\boxed{3}\cdot\boxed{3}=18

5 0
3 years ago
Evaluate the following when a= 1 ,b=3,and c =27 ( a) 6a^2+ 2bc-2c^1/3​
Dennis_Churaev [7]

Answer:

6a^2+ 2bc-2c^1/3 <u>= 162</u>

Step-by-step explanation:

  • a = 1
  • b = 3
  • c = 27

\rm 6 {a}^{2}  + 2bc - 2 {c}^{ \frac{1}{3} }

= 6 {(1)}^{2}  + 2(3)(27) - 2( {27)}^{ \frac{1}{3} }

\rm  = 6 + 162 - 2 ( \sqrt[3]{27} )

\rm  = 168 - 2(3)

\rm = 168 - 6

\boxed{\rm  = 162}

5 0
3 years ago
I need help with this. Thanks <br><br><br> I need to find the degree
scoundrel [369]

Answer:

  119.05°

Step-by-step explanation:

In general, the angle is given by ...

  θ = arctan(y/x)

Here, that becomes ...

  θ = arctan(9/-5) ≈ 119.05°

_____

<em>Comment on using a calculator</em>

If you use the ATAN2( ) function of a graphing calculator or spreadsheet, it will give you the angle in the proper quadrant. If you use the arctangent function (tan⁻¹) of a typical scientific calculator, it will give you a 4th-quadrant angle when the ratio is negative. You must recognize that the desired 2nd-quadrant angle is 180° more than that.

__

It may help you to consider looking at the "reference angle." In this geometry, it is the angle between the vector v and the -x axis. The coordinates tell you the lengths of the sides of the triangle vector v forms with the -x axis and a vertical line from that axis to the tip of the vector. Then the trig ratio you're interested in is ...

  Tan = Opposite/Adjacent = |y|/|x|

This is the tangent of the reference angle, which will be ...

  θ = arctan(|y| / |x|) = arctan(9/5) ≈ 60.95°

You can see from your diagram that the angle CCW from the +x axis will be the supplement of this value, 180° -60.95° = 119.05°.

3 0
4 years ago
NEED HELP ON ANSWERING NUMBERS 12, 13, 14,15 PLEASE 15 points
Ilya [14]
Just by looking at 14 it will be non linear since any equation that has an exponent will automatically be non linear and will not form a straight line. 13 would be linear as when you subtract x from both sides you’ll have a straight line meaning it’s linear. And 12 will be linear because the equation once into y=mx+b format it will be y=-2x/3+7/3 making a straight line if graphed correctly.
4 0
3 years ago
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