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satela [25.4K]
3 years ago
9

Mandi already has a practice ball. She is buying the light jacket, but not the lined one. She needs to buy all of the other item

s on the soccer fee list. What are her total fees for soccer. Soccer fees: game uniform- $37.50 Light jacket- $23.25 Lined jacket- $42.00 Practice ball- $22.75 Pictures- $40.50 Hair band- $2.50
Mathematics
1 answer:
seraphim [82]3 years ago
4 0
Hayskdbdbcjdnsnahshkdnf
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Jada’s teacher ask her to write a three-digit number that uses the digit 4 once and the digit 7 twice. The value of one 7 needs
viva [34]
477

The value of the first 7 from the left is 70.

If you divide 70 by 10, you get the value of the second seven, 7.

Another way to know this is equivalent fractions:

1/10 = 7/10

10 X 7 = 70
1 X 7 = 7
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4 years ago
David wants to make a box plot showing histeam's points for the year. The median score was 7, first quartile was 4, and third qu
vichka [17]
A dot above 7, 4, 10, 2, and 20. Draw a box around the median, first quartile, and and the third quartile. Then connect the box to the minimum and maximum by drawing a line. Should look like this:

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3 years ago
Q bisects PR, PQ=3y, and PR=42. Find y and QR.
Vedmedyk [2.9K]
|PR| = |PQ| + |QR|; |PQ| = |QR| conclusion |PR| = 2|PQ|

|PQ| = 3y; |PR| = 42; |QR|=?

subtitute

42 = 2(3y)
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y = 7

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3 0
3 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
3 years ago
If a x b = 2a - 3b + ab, then 3 x 5+5 x 3 is equal to?
Reptile [31]

Answer:

B 22

Step-by-step explanation:

3 0
3 years ago
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