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3 years ago

One eighth of a number ,increased by 20, is 32.Find the number

1 answer:

7 0

X - the number

$\frac{1}{8} x +20=32 \\
\frac{1}{8}x=32-20 \\
\frac{1}{8}x=12 \\
x=12 \times 8 \\
x=96$

The number is 96.

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I need help with d and I need to show my work.

cupoosta [38]

Ok
So when you multiply by a fraction just multiply top by top and bottom by bottom
So top by top is 2 by 4 so 8
And bottom by bottom is 3 by 5 which is 15
So answer is 8/15
Hope this helps and don’t forget to mark as brainliest if you thought it was most helpful :)

7 0

4 years ago

Eileen collected 98 empty cans to recycle and Carl 82 cans. They packed a equal number of cans into each of three boxes. How man

Sonbull [250]

Answer: 60 cans in each box

Step-by-step explanation:

98+82=180

180/3=60

8 0

3 years ago

If the base is 4, what is the value if the exponent is 2? What if the exponent is -2?

Vikentia [17]

Answer:

In the world of exponents, 4 is the number being raised by the exponent, which is 2.

Let's answer the first question:

If the base is 4, what is the value if the exponent is 2?

The base is 4 and the exponent is 2. We would multiply 4 two times.

$4^2= 4*4 = 16$

So, it would be 16.

Let's answer the second question:

What if the exponent is -2?

<u>This is the rule for negative exponents:</u>

$a^{-x}=\frac{1}{a^x}$

Using this rule, we can solve $4^{-2}$ .

$4^{-2}= \frac{1}{4^2}=\frac{1}{16}$

So, our answer for the 2nd question is 1/16.

3 0

4 years ago

Rafeeq bought a field in the form of a quadrilateral (ABCD)whose sides taken in order are respectively equal to 192m, 576m,228m,

Valentin [98]

Answer:

a. 85974 m²

b. 17,194,800 AED

c. 18,450 AED

Step-by-step explanation:

The sides of the quadrilateral are given as follows;

AB = 192 m

BC = 576 m

CD = 228 m

DA = 480 m

Length of a diagonal AC = 672 m

a. We note that the area of the quadrilateral consists of the area of the two triangles (ΔABC and ΔACD) formed on opposite sides of the diagonal

The semi-perimeter, s₁, of ΔABC is found as follows;

s₁ = (AB + BC + AC)/2 = (192 + 576 + 672)/2 = 1440/2 = 720

The area, A₁, of ΔABC is given as follows;

$Area\, of \, \Delta ABC = \sqrt{s_1\cdot (s_1 - AB)\cdot (s_1-BC)\cdot (s_1 - AC)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times (720 - 192)\times (720-576)\times (720 - 672)}$

$Area\, of \, \Delta ABC = \sqrt{720 \times 528 \times 144 \times 48}$ = 6912·√(55) m²

Similarly, area, A₂, of ΔACD is given as follows;

$Area\, of \, \Delta ACD= \sqrt{s_2\cdot (s_2 - AC)\cdot (s_2-CD)\cdot (s_2 - DA)}$

The semi-perimeter, s₂, of ΔABC is found as follows;

s₂ = (AC + CD + D)/2 = (672 + 228 + 480)/2 = 690 m

We therefore have;

$Area\, of \, \Delta ACD = \sqrt{690 \times (690 - 672)\times (690 -228)\times (690 - 480)}$

$Area\, of \, \Delta ACD = \sqrt{690 \times 18\times 462\times 210} = \sqrt{1204988400} = 1260\cdot \sqrt{759} \ m^2$

Therefore, the area of the quadrilateral ABCD = A₁ + A₂ = 6912×√(55) + 1260·√(759) = 85973.71 m² ≈ 85974 m² to the nearest meter square

b. Whereby the cost of 1 meter square land = 200 AED, we have;

Total cost of the land = 200 × 85974 = 17,194,800 AED

c. Whereby the cost of fencing 1 m = 12.50 AED, we have;

Total perimeter of the land = 576 + 192 + 480 + 228 = 1,476 m

The total cost of the fencing the land = 12.5 × 1476 = 18,450 AED

4 0

3 years ago

Which equation is represented by the graph below?

aleksandr82 [10.1K]

The are you have selected

5 0

3 years ago