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2 years ago

12

PLZ HELP!!!! WILL MARK BRAINLYIST!!!!

1 answer:

pychu [463]2 years ago

3 0

Answer:

* 5+2k+n

Step-by-step explanation:

Combine all like terms:

7-2 = 5

5k-3k = 2k

n = n

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$30 board game on sale for $20.10

VMariaS [17]

Ok so to solve for percent off
percent off means discount

so therefor we need to find how much was discounted
30-20.10=9.90

so we see that 9.90 was discounted
to find the percent we do
discount/total=percent discount
9.90/30=0.33

percent means parts out of 100
0.33/1 times 100/100=33/100=33%

answer is 33% discout

6 0

2 years ago

Log 15 (2x − 2) = log 15 (x+9)

notka56 [123]

Answer:

$x=11$

Step-by-step explanation:

Given the equation

$\log_{15}(2x-2)=\log_{15}(x+9)$

Note that

$2x-2>0\\ \\2x>2\\ \\x>1$

and

$x+9>0\\ \\x>-9$

Combined, $x>1$

Solve the equation:

$2x-2= x+9\\ \\2x-x=9+2\\ \\x=11$

Since $11>1,$ this is the solution to the equation.

5 0

3 years ago

The original price and percent paid of a 20% discount and a $14.40 sale price.

Vikentia [17]

Your answer is $18.00

Because 14.40 x 100/80 =$18

Hope this helps

Please please please like my comment

3 0

2 years ago

51% of the tickets sold at a school carnival were early-admission tickets. If the school sold 100 tickets in all, how many early

saul85 [17]

Answer:

51 were the total number of the tickets sold at a school carnival were early-admission tickets.

Step-by-step explanation:

Total number of tickets sold by = 100

Let $x$ be the early-admission tickets sold by the school.

As 51% of the tickets sold at a school carnival were early-admission tickets.

so

$x=\frac{51}{100}\times 100$

$= 51$

Therefore, 51 were the total number of the tickets sold at a school carnival were early-admission tickets.

5 0

2 years ago

This one please. Thank you!!

lys-0071 [83]

I’m believe it’s the 3rd one but i’m not sure

5 0

2 years ago

Read 2 more answers