A technician upgraded the memory on a server from two 8GB sticks to eight 32GB. The server memory is now at full capacity per th
1 answer:
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Answer:
Explanation:
The following Python program uses a combination of dictionary, list, regex, and loops to accomplish what was requested. The function takes a file name as input, reads the file, and saves the individual words in a list. Then it loops through the list, adding each word into a dictionary with the number of times it appears. If the word is already in the dictionary it adds 1 to its count value. The program was tested with a file named great_expectations.txt and the output can be seen below.
import re
def wordCount(fileName):
file = open(fileName, 'r')
wordList = file.read().lower()
wordList = re.split('\s', wordList)
wordDict = {}
for word in wordList:
if word in wordDict:
wordDict[word] = wordDict.get(word) + 1
else:
wordDict[word] = 1
print(wordDict)
wordCount('great_expectations.txt')
Answer:
Check the explanation
Explanation:
def get_list_of_integers_from_file(filename):
int_list=[]
for line in open(filename).readlines():
try:
int_list.append(int(line))
except:
continue
return int_list
print(get_list_of_integers_from_file('file.txt'))
File.txt:
Kindly check the output below.
