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3 years ago

List of programming languages and their typing

Computers and Technology

2 answers:

ycow [4]3 years ago

7 0

Types of Programming Languages:-

Procedural Programming Language
Functional Programming Language
Object-oriented Programming Language
Scripting Programming Language
Logic Programming Language

densk [106]3 years ago

5 0

The list of programmers languages i know
Q-basic
C+
C++

You might be interested in

Determine whether or not the following pairs of predicates are unifiable. If they are, give the most-general unifier and show th

Evgen [1.6K]

Answer:

a) P(B,A,B), P(x,y,z)

=> P(B,A,B) , P(B,A,B}

Hence, most general unifier = {x/B , y/A , z/B }.

b. P(x,x), Q(A,A)

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q.

c. Older(Father(y),y), Older(Father(x),John)

Thus , mgu ={ y/x , x/John }.

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))

This is not unifiable as x cannot be bound for both A and B.

e) P(f(x), x, g(x)), P(f(y), A, z)

=> P(f(A), A, g(A)), P(f(A), A, g(A))

Thus , mgu = {x/y, z/y , y/A }.

Explanation:

Unification: Any substitution that makes two expressions equal is called a unifier.

a) P(B,A,B), P(x,y,z)

Use { x/B}

=> P(B,A,B) , P(B,y,z)

Now use {y/A}

=> P(B,A,B) , P(B,A,z)

Now, use {z/B}

=> P(B,A,B) , P(B,A,B}

Hence, most general unifier = {x/B , y/A , z/B }

b. P(x,x), Q(A,A)

No mgu exists for this expression as any substitution will not make P(x,x), Q(A, A) equal as one function is of P and the other is of Q

c. Older(Father(y),y), Older(Father(x),John)

Use {y/x}

=> Older(Father(x),x), Older(Father(x),John)

Now use { x/John }

=> Older(Father(John), John), Older(Father(John), John)

Thus , mgu ={ y/x , x/John }

d) Q(G(y,z),G(z,y)), Q(G(x,x),G(A,B))

Use { y/x }

=> Q(G(x,z),G(z,x)), Q(G(x,x),G(A,B))

Use {z/x}

=> Q(G(x,x),G(x,x)), Q(G(x,x),G(A,B))

This is not unifiable as x cannot be bound for both A and B

e) P(f(x), x, g(x)), P(f(y), A, z)

Use {x/y}

=> P(f(y), y, g(y)), P(f(y), A, z)

Now use {z/g(y)}

P(f(y), y, g(y)), P(f(y), A, g(y))

Now use {y/A}

=> P(f(A), A, g(A)), P(f(A), A, g(A))

Thus , mgu = {x/y, z/y , y/A }.

7 0

3 years ago

a user reports that his dot matrix printer is printing dark and clear on the left of the paper but that the print is very light

yarga [219]

Answer:

Correctly position the platen of the printer to hold the paper in place.

Explanation:

Since the dot matrix printer is printing dark and clear on the left of the paper but very light on the right side of the paper, it is possible that the paper is not being held properly. So adjusting the platen will hold the paper properly and hence uniform prints on the paper.

Note: Dot matrix printers are printers that print closely related dots to form require texts (shapes) by striking some pins against an ink ribbon.

Some of the parts of these printers are; power supply, carriage assembly, Paper sensor, ribbon, platen and pins.

4 0

3 years ago

A researcher plans to identify each participant in a certain medical experiment with a code consisting of either a single letter

trapecia [35]

Answer:

5 Letters

Explanation:

So we need 12 distinct codes made of a single letter or a pair of letters.

What would be the least number of letters?

Lets try with 3 letters A, B and C

The possible combinations are: A, B, C, AB, AC, BC

These are 6 codes and we need 12 so lets try more A, B, C and D

The possible combinations are: A, B, C, D, AB, AC, AD, BC, BD, CD

These are 10 codes and we need 12 so lets try more A, B, C, D and E

The possible combinations are:

A, B, C, D, E, AB, AC, AD, AE, BC, BD, BE, CD, CE, DE

Finally we got 15 distinct codes which are more than 12 so the least number of letters needed are 5.

Using formula:

Four letters = 4C1 + 4C2 = 4 + 6 = 10

Five letters = 5C1 + 5C2 = 5 + 10 = 15

5 0

3 years ago

Meg[] elements = {new Lois(), new Stewie(), new Meg(), new Brian()}; for (int i =0; i

Stells [14]

Complete question is attached as snapshot.

Answer:

This will result in a compilation error.

Here's the inheritance hierarchy:

Meg -> Lois -> Brian -> Stewie

Now Meg has 2 public Fxns, a() and toString().

Lois inherits from Meg and all its public functions as well but, overrides the a() fxn of its super class.

So finally Lois has fxns a(), b() and toString().

Brian extends Lois and inherits all the above listed fxns of Lois, but overrides the b() and toString() fxns.

Stewie extends Brian and inherits all the fxns of Brian, but overrides the a() and toString() fxns.

In the Main driver fxn, we call a() and b() methods of all these classes but, the base class Meg has no b() and it is not extending any class so its not available in its scope.

This results in a compilation error.

Explanation:

7 0

3 years ago

Write a method named square that accepts an integer argument and returns the square of that argument.

BaLLatris [955]

Answer:

The method is as follows:

double square(int num){

return num*num;

}

Explanation:

Written in C++

This first line defines the method

double square(int num){

This line returns the square of num

return num*num;

}

<em>I've added the full program as an attachment where I include the main method</em>

Download cpp

7 0

3 years ago