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mr_godi [17]
3 years ago
9

Statistics math help please! Need to get grade up!

Mathematics
1 answer:
Anuta_ua [19.1K]3 years ago
6 0

The frequency refers to how many times a test scores within that particular range.

To find this answer, we must divide the number of scores we are interested in by the number of total scores, aka (n/500).

We are interested in the range of 70-89, and we notice there are 2 boxes included in this range: 70-79 and 80-89.

In the 70-79 range we see that there are 172 out of 500 scores.

In the 80-89 range we see that there are 105 out of 500 scores.

If you add these scores, you are given 277 out of 500 scores, aka (277/500), which gives us 0.554

You were on the right track with the answer you chose but you just forgot to include the 80-89 range. Hope this helps!

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krok68 [10]
A. Y would be 14 since 2w would equal -8, and -8+14=6.
B. Y would be -14 because 2w would equal 20 and 20+(-14)=6
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Bradley and Kelly are out flying kites at a park one afternoon. A model of Bradley and Kelly's kites are shown below on the coor
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The correct answer is:

C. They are similar because the corresponding sides of kites KELY and BRAD all have the relationship 2:1.

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d=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

the lengths of the sides of BRAD are:

\text{BR}=\sqrt{(7-6)^2+(3-4)^2}=\sqrt{1^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}\\\\\text{RA}=\sqrt{(6-3)^2+(4-3)^2}=\sqrt{3^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{AD}=\sqrt{(3-6)^2+(3-2)^2}=\sqrt{(-3)^2+1^2}=\sqrt{9+1}=\sqrt{10}\\\\\text{DB}=\sqrt{(6-7)^2+(2-3)^2}=\sqrt{(-1)^2+(-1)^2}=\sqrt{1+1}=\sqrt{2}

The lengths of the sides of KELY are:

\text{KE}=\sqrt{(2-0)^2+(11-9)^2}=\sqrt{2^2+2^2}=\sqrt{4+4}=\sqrt{8}=2\sqrt{2}\\\\\text{EL}=\sqrt{(0-2)^2+(9-3)^2}=\sqrt{(-2)^2+6^2}=\sqrt{40}=2\sqrt{10}\\\\\text{LY}=\sqrt{(2-4)^2+(3-9)^2}=\sqrt{(-2)^2+(-6)^2}=\sqrt{40}=2\sqrt{10}\\\\\text{YK}=\sqrt{(4-2)^2+(9-11)^2}=\sqrt{2^2+(-2)^2}=\sqrt{8}=2\sqrt{2}

Each side of KELY is twice the length of the corresponding side on BRAD.  This makes the ratio of the sides 2:1 and the figures are similar.

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In real life, a scale copy is often smaller than the original figure.

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