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11111nata11111 [884]
3 years ago
10

Help ASAP please and thanks

Mathematics
2 answers:
AveGali [126]3 years ago
7 0
The first one is correct.
Firlakuza [10]3 years ago
4 0
The first one includes both
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Is the perpendicular bisector of a line segment also an angle bisector?
algol13

Answer:

yes

Step-by-step explanation:

In an isosceles triangle, one perpendicular bisector is also an angle bisector.

8 0
2 years ago
So I'm not good with story problems and im trying to figure this one question out. How do I format it?​
sashaice [31]

Answer:   $76,000

<u>Step-by-step explanation:</u>

State Income Tax = Salary × Income Tax Rate

                   3040 = Salary × 0.04

              <u>   ÷ 0.04 </u>    <u>            ÷0.04 </u>

                76,000 = Salary

5 0
3 years ago
A delivery truck drove 203 mi in 3.5 h. After unloading and loading new cargo, it traveled on another 243 mi for 4.5 h.
sveticcg [70]
The answer is 55.75! Trust me I took a test on this and its the right one.
8 0
3 years ago
Read 2 more answers
Which values of k would cause this system of equations to have no solution? Check all that apply.
xeze [42]

Answer:

x= -2y/3

-4y+4y=14

0y= 14

This has no solution.

Step-by-step explanation:

Answer In cases of two equations having two unknown variables the simultaneous method of solving the equations is adopted.

Supposing “0” as the value of “k” we will have the equation as 3x+2y=0

Then separating variable x will give, x= -2y/3

Substituting the value of x into the first equation that is: 6x + 4y = 14

6(-2y/3)+4y=14

Expanding this we get: 6(-2y/3)+4y=14

-4y+4y=14

0y= 14

Thus, no solution.

5 0
3 years ago
Read 2 more answers
Explain how you got the answer
Gnoma [55]

Answer:

\huge\boxed{Center = (3,3),Radius = 2\sqrt{15} }

Step-by-step explanation:

<u><em>Given equation is</em></u>

x^2 + y^2 -6x-6y -42 = 0

Adding 42 to both sides

x^2 + y^2 -6x-6y = 42\\

Completing squares

x^2 -6x+y^2 -6x = 42\\(x)^2 - 2(x)(3) +y^2 - 2(y)(3) = 42

Adding (3)² => 9 and (3)² => 9 to both sides

(x-3)^2+(y-3)^2 = 42+9+9\\(x-3)^2 + (y-3)^2 = 60\\(x-3)^2  (y-3)^2 = (2{\sqrt{15})^2}

Comparing it with (x-h)^2+(y-k)^2 = r^2 where Center = (h,k) and Radius = r

We get:

Center = (3,3)

Radius = 2\sqrt{15}

7 0
3 years ago
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