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Elina [12.6K]
3 years ago
5

Select all that apply. (abc) 2 = This expression without exponents is abcabc aabbcc a 2 b 2 c 2 ababab

Mathematics
2 answers:
VLD [36.1K]3 years ago
8 0

Answer:

aabbcc

abcabc

Step-by-step explanation:

(abc) ^2

(abc) * (abc)

abc abc

a* a* b* b* c* c

The third terms tries to trick you.  It is equal, but it has exponents

The fourth terms does not have any "c" terms

liubo4ka [24]3 years ago
5 0

Answer:

A. abcabc

B. aabbcc

Step-by-step explanation:

We have been given an expression (abc)^2. We are asked to choose the correct options that our equivalent to our given expression without exponents.

Let us check our given choices one by one.

A. abcabc

We know (mn)^2=mn\cdot mn, therefore, option A is the correct choice.

B. aabbcc

We know x^2=x\cdot x. So, we can rewrite our given expression as:

(abc)^2\rightarrow a^2b^2c^2=a\cdot a\cdot b\cdot b\cdot c\cdot c=aabbcc

Therefore, option B is the correct choice.

C. a^2b^2c^2

Since option C contains exponents, therefore, option C is not correct choice.

D. aabb

Since term cc is missing from option D, therefore, it is not a correct choice.

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Answer:

y=-2x-4

Step-by-step explanation:

When an equation is perpendicular, then it is the equation's inverse. The inverse of 1/2 is -2

The y-intercept is b in y=mx+b. In this equation, b=-4

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2 years ago
Find -32.3 - (-16.3).
pentagon [3]

Answer:

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Step-by-step explanation:

-32.3 - (-16.3).

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-32.3 + 16.3

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8 0
3 years ago
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Julia has to mow two yards.She will need 13/16 gallon of gas to mow the first yard and 2/5 gallon to mow the second yard. She ha
solong [7]

Answer:

Julia has enough gallons of gas to mow the two yards.

Step-by-step explanation:

Given:

Total yards Julia has to mow = 2

Gas in gallons required for the 1st yard = \frac{13}{16}

Gas in gallons required for the 1st yard = \frac{2}{5}

Gallons of gas Julia has = 1\frac{1}{2}.

To find if she has enough gas to mow the two yards.

Solution:

In order to find the total gas she would require to mow two yards, we will add the amounts of gas required for each yard.

<em>Total amount of gas required to mow 2 yards is :</em>

<em>⇒ Gallons of gas required for 1st yard + Gallons of gas required for 2nd yard</em>

⇒ \frac{13}{16}+\frac{2}{5}

<em>To add fractions we will need take least common denominator between 16 and 5. </em>

On comparing the multiples of 16 and 5, we find out the least common multiple is 80.

To make the denominators common, we will multiply the numerators and denominators with such a number that gives 80 as denominator.

So, we have:

⇒ \frac{13\times 5}{16\times 5}+\frac{2\times 16}{5\times 16}

⇒ \frac{65}{80}+\frac{32}{80}

Then, we add the numerators.

⇒ \frac{97}{80}

⇒ 1.21 gallons

Julia has 1\frac{1}{2} gallons of gas which is = 1.5 gallons.

Since 1.5>1.21, therefore we can say Julia has enough gallons of gas to mow the two yards.

8 0
3 years ago
You want to buy shoes and the The price is 40 and you buy it 10 days after and it is 1/5% off .
Mamont248 [21]
8 I think I don’t know the question you’re looking for.
6 0
3 years ago
Each deli sandwhiches made uses 8/8 pound of roast beef.Marisa started with 5 pounds of roast beef and now has 2 3/4 pounds left
OleMash [197]

Answer:

Marisa has made 6 sandwiches.

Step-by-step explanation:

The pounds of roast beef required to make each sandwiches is \frac{3}{8}, and not \frac{8}{8} as erroneously typed in the question.

Given that each deli sandwiches made, uses \frac{3}{8} pounds of roast beef.

Marisa started with 5 pounds, and had 2\frac{3}{4} pounds left.

Thus,

pounds of roast beef used = 5 - 2\frac{3}{4}

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                                             = \frac{9}{4}

                                             = 2\frac{1}{4}

Marisa had used 2\frac{1}{4} pounds of roast beef. So that;

the number of del sandwiches made = 2\frac{1}{4} ÷ \frac{3}{8}

                                                    = \frac{9}{4} ÷ \frac{3}{8}

                                                    = 6

Therefore, the number of sandwiches made by Marisa is 6.

5 0
3 years ago
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