Hello damerahli!
Find the landmark.
Let's take a look at the graph. The coordinates given are (2, ¼).
This means that...
- Coordinate at abscissa = 2
- Coordinate at ordinate = ¼
In the graph given, each square = ¼ units. That means the 1st box above the origin in the ordinate is (0, ¼). Let's mark this as our coordinate of y-axis. Then let's take 2 in the abscissa (2, 0) as the other coordinate. So, by connecting the 2 points (since both the coordinates are positive they'll lie in the 1st quadrant) we can see that the landmark is the 
. (Marked as a yellow dot in the attached figure).
<em>Please </em><em>refer </em><em>to </em><em>the attached</em><em> picture</em><em> for</em><em> better</em><em> understanding</em><em>.</em>
__________________
Hope it'll help you!
ℓu¢αzz ッ
The given equation for the relationship between a planet's orbital period, T and the planet's mean distance from the sun, A is T^2 = A^3.
Let the orbital period of planet X be T(X) and that of planet Y = T(Y) and let the mean distance of planet X from the sun be A(X) and that of planet Y = A(Y), then
A(Y) = 2A(X)
[T(Y)]^2 = [A(Y)]^3 = [2A(X)]^3
But [T(X)]^2 = [A(X)]^3
Thus [T(Y)]^2 = 2^3[T(X)]^2
[T(Y)]^2 / [T(X)]^2 = 2^3
T(Y) / T(X) = 2^3/2
Therefore, the orbital period increased by a factor of 2^3/2
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Answer:
D - The slope from point O to point A is three times the slope of the line from point A to point B.
P=2
<span>17-2p=2p+5+2p P=2
I hope this helps.
Can you make my answer the brainliest please?
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Which of the sets of ordered pairs represents a function? (4 points) A = {(−4, 5), (1, −1), (2, −2), (2, 3)} B = {(2, 2), (3, −2
elena55 [62]
A function will not have any repeating x values....it can have repeating y values, just not the x ones
(-4,5),(-1,1),(2,-2),(2,3)
this is not a function because it has 2 sets of points that has x as 2...so it has repeating x values
(2,2),(3,-2),(9,3),(9,-3)
this is not a function because it has 2 sets of points that has an x value of 9...so it also has repeating x values
so both of these are not functions.....neither of them
