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SCORPION-xisa [38]
3 years ago
13

Can you please help me with my algebra?

Mathematics
1 answer:
Zolol [24]3 years ago
7 0
(16)

47.5+81.5=129

129÷2=64.5
64.5-17=47.5
64.5+17=81.5


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charlene has eight more dollars than Megan. Together they have $86.00. Which equiation can be used to determine the amount of mo
Paul [167]

Answer:

Megan has 35.00 dollars.

Step-by-step explanation:

Divide 86.00 by 2 which equals 43.00.  Next, minus 8 from the 43.00 and you will get what Megan has.  Megan has 35.00 dollars.

I hope this helps!

8 0
2 years ago
Solve for the given variable 3(2x+5)=4x+21
Nookie1986 [14]

Answer:

x=3

Step-by-step explanation:

3(2x+5)=4x+21

6x+15=4x+21

-4x            -4x

2x+15= 21

     -15    -15

2x=6

2     2

<h2>x=3                          Hope that helped!!!!</h2>
6 0
3 years ago
a right rectangular prism has a length of 8 centimeters width of 10 centimeters and height of 10 centimeters the volume of the p
nata0808 [166]

Answer:

800

Step-by-step explanation:

8*10*10=

8*10=

80*10=

800cm.

i broke up the problem. hope this helps!

4 0
3 years ago
Read 2 more answers
What is the value of x in equation 0.2(x+1)+ 0.5x = - 0.3(x-4)
Greeley [361]

Answer: x=1

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
In a class of 19 students, 3 are math majors. A group of four students is chosen at random. (Round your answers to four decimal
KatRina [158]

Answer:

(a) The probability is 0.4696

(b) The probability is 0.5304

(c) The probability is 0.0929

Step-by-step explanation:

The total number of ways in which we can select k elements from a group n elements is calculate as:

nCx=\frac{n!}{x!(n-x)!}

So, the number of ways in which we can select four students from a group of 19 students is:

19C4=\frac{19!}{4!(19-4)!}=3,876

On the other hand, the number of ways in which we can select four students with no math majors is:

(16C4)*(3C0)=(\frac{16!}{4!(16-4)!})*(\frac{3!}{0!(3-0)!})=1820

Because, we are going to select 4 students form the 16 students that aren't math majors and select 0 students from the 3 students that are majors.

At the same way, the number of ways in which we can select four students with one, two and three math majors are 1680, 360 and 16 respectively, and they are calculated as:

(16C3)*(3C1)=(\frac{16!}{3!(16-3)!})*(\frac{3!}{1!(3-1)!})=1680

(16C2)*(3C2)=(\frac{16!}{2!(16-2)!})*(\frac{3!}{2!(3-1)!})=360

(16C1)*(3C3)=(\frac{16!}{1!(16-1)!})*(\frac{3!}{3!(3-3)!})=16

Then, the probability that the group has no math majors is:

P=\frac{1820}{3876} =0.4696

The probability that the group has at least one math major is:

P=\frac{1680+360+16}{3876} =0.5304

The probability that the group has exactly two math majors is:

P=\frac{360}{3876} =0.0929

6 0
3 years ago
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