Answer: " m = zC / (C − z) " .
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Explanation:
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Given: 1/C + 1/m = 1/z ; Solve for "m".
Subtract "1/C" from each side of the equation:
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1/C + 1/m − 1/C = 1/z − 1/C ;
to get: 1/m = 1/z − 1/C ;
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Now, multiply the ENTIRE EQUATION (both sides); by "(mzC"); to get ride of the fractions:
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mzC {1/m = 1/z − 1/C} ;
to get: zC = mC − mz ;
Factor out an "m" on the "right-hand side" of the equation:
zC = m(C − z) ; Divide EACH side of the equation by "(C − z)" ; to isolate "m" on one side of the equation;
zC / (C − z) = m(C − z) / m ; to get: 24/8 = 3 24
zC/ (C − z) = m ; ↔ m = zC/ (C − z) .
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The range of sample statistics obtained when many samples are selected is a sampling distribution. A sampling distribution is also a probability distribution of the statistics obtained in the large number of samples drawn from a specific population. It also shows every possible result that the statistic can take in every possible sample from the population and how often will each results happens.
Answer:
i think its the last option.
Step-by-step explanation:
its not the first one because they it can be proved using AAS (but that option isnt available)
You can't prove it with SSS or ASA without more info
AAA doesn't exist
theirfore it must be the last option.
Answer:
Assignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques
Step-by-step explanation:
Assignment: 01.07 LaboratoryAssignment: 01.07 Laboratory Techniques TechniquesAssignment: 01.07 Laboratory TechniquesAssignment: 01.07 Laboratory Techniques
The answer for this would be 0.06.
