The slope of the line that is perpendicular to 6x + 2y = -32 is: 1/3.
<h3>What is the Slope of Perpendicular Lines?</h3>
The slope of two lines that are perpendicular to each other will always have a product that is equal to -1, which means that their slopes are negative reciprocals to each other.
Rewrite 6x + 2y = -32 in slope-intercept form:
2y = -6x - 32
2y/2 = -6x/2 - 32/2
y = -3x - 16
The slope is -3. Negative reciprocal of -3 is 1/3.
Therefore, the slope of the perpendicular line would be: 1/3.
Learn more about the slope of perpendicular lines on:
brainly.com/question/1362601
#SPJ1
Equation of an ellipse
→having center (0,0) , vertex (
and covertex
and focus
is given by:

As definition of an ellipse is that locus of all the points in a plane such that it's distance from two fixed points called focii remains constant.
Consider two points (a,0) and (-a,0) on Horizontal axis of an ellipse:
Distance from (a,0) to (c,0) is = a-c = 
Distance from (-a,0) to (c,0) is = a + c = 
a -c + a +c
= a + a
= 2 a →(Option A )
Answer:
The x-intercept is 2.
Step-by-step explanation:
![2 \sqrt[3]{x - 10} + 4 = 0](https://tex.z-dn.net/?f=2%20%5Csqrt%5B3%5D%7Bx%20-%2010%7D%20%20%2B%204%20%3D%200)
![2 \sqrt[3]{x - 10} = - 4](https://tex.z-dn.net/?f=2%20%5Csqrt%5B3%5D%7Bx%20-%2010%7D%20%20%3D%20%20-%204)
![\sqrt[3]{x - 10 } = - 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7Bx%20-%2010%20%7D%20%20%3D%20%20-%202)


Answer:
-9h² - 12h - 3
Step-by-step explanation:
Follow the FOIL method:
FOIL = First, Outside, Inside, Last
Multiply the terms together:
First: 9h * -h = -9h²
Outside: 9h * -1 = -9h
Inside: 3 * -h = -3h
Last: 3 * -1 = -3
Combine like terms: 9h² + (-9h - 3h) - 3
9h² - 12h - 3
-9h² - 12h - 3 is your answer.
~
The value of 4 is 4,000 (four thousand)