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Karolina [17]
3 years ago
9

3/x + 4/y = 2 linear equation?

Mathematics
1 answer:
daser333 [38]3 years ago
8 0

Answer:

Linear

Step-by-step explanation:

When you graph them, they do not hit each other.

Linear equation in standard form is Ax+By=C

If it is in this form it is linear.

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Write a rule for the translation.
CaHeK987 [17]
Answer: b
Explanation: to get to point c (pink) to the other point c (blue) you need to go back 2 spaces which will makes it negative and go up one space which is positive.
8 0
3 years ago
What percentage of the actual salary are the actual total expenses?
Setler79 [48]

Answer:

95.97%

Step-by-step explanation:

Observing the table we have

The actual salary is $3,600 -----> This amount represent the 100%

The actual total expenses are $3,455

using proportion

Find out what percentage of the actual salary are the actual total expenses

\frac{100}{3,600}=\frac{x}{3,455}\\ \\ x=100*3,455/3,600\\ \\ x=95.97\%

7 0
3 years ago
Which of the following statements is TRUE regarding b(x)?
Zinaida [17]
D since it’s slope is negative from [0,1] and negative below the x axis
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3 years ago
Find g(x), where g(x) is the translation 7 units up of f(x)=x.
hammer [34]
G(x)=x+7 is the translation
8 0
3 years ago
What kind of shift does the graph have? y = -sin (x-1) from y = sin(x)
Mademuasel [1]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\
% function transformations for trigonometric functions
\begin{array}{rllll}
% left side templates
f(x)=&{{  A}}sin({{  B}}x+{{  C}})+{{  D}}
\\\\
f(x)=&{{  A}}cos({{  B}}x+{{  C}})+{{  D}}\\\\
f(x)=&{{  A}}tan({{  B}}x+{{  C}})+{{  D}}
\end{array}
\\\\
-------------------\\\\

\bf \bullet \textit{ stretches or shrinks}\\
\quad \textit{horizontally by amplitude } |{{  A}}|\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{function period or frequency}\\
\left. \qquad  \right. \frac{2\pi }{{{  B}}}\ for\ cos(\theta),\ sin(\theta),\ sec(\theta),\ csc(\theta)\\\\
\left. \qquad  \right. \frac{\pi }{{{  B}}}\ for\ tan(\theta),\ cot(\theta)

now, with that template in mind, let's see

\bf \begin{array}{lllll}
y=&-1sin(&1x&-1)&+0\\
&A&B&C&D
\end{array}
\\\\\\
\textit{horizontal shift of }\cfrac{C}{B}\implies \cfrac{-1}{1}\implies -1
\\\\\\
\textit{A is negative, so is flipped upside-down}
8 0
3 years ago
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