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3 years ago

julia has framed one of her paintings. the painting is square, and the frame is 5cm wide. please help with questions a-d

Mathematics

1 answer:

Brilliant_brown [7]3 years ago

7 0

i) x²

ii) (x-10)²

b) (x-10)² = x² - 20x + 100

c) (30-10)² = 400 cm²

d) (x-10)² = 144 => x-10 = √144 => x = 12 + 10 = 22 cm

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Trying to figure out 2 different equivalent fractions for the following fractions if something is divided into 8 sections

irina [24]

2/4 is equivalent to 1/16 and 1/128 if dived by 8 sections
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1/2 is equivalent to 1/16 and 1/128 if dived by 8 sections
3/4 is equivalent to 3/32 and 3/256 if dived by 8 sections
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2 years ago

Read 2 more answers

Find the rule, and type the missing number in the sequence.<br><br> 96, 192, ____, 384

Wittaler [7]

Answer:

Missing number is 288, and the rule is +96

Step-by-step explanation:

First subtract 96 from 192, which is 96

then add that to 192 and the missing value is 288

you should also add 96 to 288 just to make sure it gets you to the last number which is 384.

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2 years ago

Amanda spent a total of 70 minutes competing her chores this week. Write and solve an equation to represent the number of minute

gtnhenbr [62]

Answer:

28 minutes spent in washing the dishes.

Step-by-step explanation:

Given the table

Chore time in minutes

Sweeping 42

Dishes ?

Amanda spent a total of 70 minutes competing her chores this week

Total of 70 minutes spent

42 minutes spent in sweeping . to find the number of minutes Amanda spent in washing the dishes , subtract 42 minutes from the total time spent

let x be the number of minutes spent washing the dishes

$42+x=70$

To solve for x , subtract 42 from both sides

$42+x=70\\x= 70-42\\x=28$

28 minutes spent in washing the dishes.

4 0

2 years ago

What is the coefficient and degree of 6v^7

Dmitriy789 [7]

I believe v is your coefficient and the degree is 7

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2 years ago

The heights of young women follow a Normal distribution with a mean u = 64.5 inches and standard deviation o = 2.5 inches. The p

mash [69]

Answer:

The heights of young women follow a Normal distribution with a mean u = 64.5 inches and standard deviation o = 2.5 inches. The probability that the mean height of an SRS of 10 young women exceeds 66.5 inches is ＿

normalcdf(66.5, 99999999, 64.5, 2.5)

1 - normalcdf(66.5, 99999999, 64.5, 0.7906)

normalcdf(-99999999, 66.5, 64.5, 2.5)

normalcdf(66.5, 99999999, 64.5, 0.7906)

normalcdf(66.5, 99999999, 0, 1)

1 - normalcdf(66.5, 99999999, 64.5, 2.5)

1 - normalcdf(66.5, 99999999, 0, 1)

normalcdf(--99999999, 66.5, 64.5, 0.7906)

plz need help number 1 2 3 4 5 are pic

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2 years ago