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3 years ago

I WILL GIVE YOU BRAINLIEST AND I WILL PAYPAL YOU 5 BUCKS, PLEASEE JUST SOMEONE ANSWER THIS QUESTION FOR ME

2 answers:

7 0

When you rotate across the x-axis it will be in quadrant 4 now and then when rotating a point 180 degrees counterclockwise about the origin our point A(x,y) becomes A'(-x,-y). So all you do is make both x and y negative.
hope this helps:))

stepan [7]3 years ago

5 0

Answer:

Quadrant 2

Step-by-step explanation:

It goes over the x axis and rotates 180 which is half a a circle.

Haha you don't got to pay someone to help you bro

You might be interested in

In a circle an arc length 10 is intercepted by a central angle of 2/3 radius

djverab [1.8K]

We have been given that in a circle an arc length 10 is intercepted by a central angle of 2/3. We are supposed to find the radius of the circle.

We will use arc-length formula to solve our given problem.

$l=r\theta$ , where,

$l$ = Arc length,

$r$ = Radius,

$\theta$ = Central angle corresponding to arc length.

Upon substituting our given values in arc-length formula, we will get:

$10=r\cdot \frac{2}{3}$

$10\cdot \frac{3}{2}=r\cdot \frac{2}{3}\cdot \frac{3}{2}$

$5\cdot \frac{3}{1}=r$

$15=r$

Therefore, the radius of the given circle would be 15 units.

5 0

3 years ago

To prepare for a triathlon, Amanda starts from position A and rides her bike along a straight road for 12 miles to reach positio

Sergio [31]

Answer:

Step-by-step explanation:

Let's draw the given information first for better understanding . Check the image attached.

We can use cosine rule to find the angles .

for angle A ,

$Cos A =\frac{b^2+c^2-a^2}{2bc}$

$Cos A =\frac{20^2+12^2-15^2}{2*20*12}$

$Cos A =\frac{319}{480}$

m∠A = 48.35 degrees

Similarly for angle B

$Cos B =\frac{a^2+c^2-b^2}{2bc}$

$Cos B =\frac{15^2+12^2-20^2}{2*15*12}$

$Cos B =\frac{-31}{360}$

m∠B = 94.94 degrees

Now use A+B+C=180 degrees

48.35+94.94+C=180

C=180-48.35-94.94

m∠C = 36.71 degrees

3 0

4 years ago

Read 2 more answers

4+8/2* (6-3). Please answerrrr

Andrew [12]

Answer:

Step-by-step explanation:

brainliest plss

5 0

3 years ago

Read 2 more answers

From a group of 12 students, we want to select a random sample of 4 students to serve on a university committee. How many combin

borishaifa [10]

Answer:

495 combinations of 4 students can be selected.

Step-by-step explanation:

The order of the students in the sample is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

How many combination of random samples of 4 students can be selected?

4 from a set of 12. So

$C_{n,x} = \frac{12!}{4!(8)!} = 495$

495 combinations of 4 students can be selected.

8 0

3 years ago

An architect's scale drawing of a new school is 8.4 inches long. The scale used in the drawing is 2 inches = 8 feet.

Brut [27]

Answer:

33.6f eet

Step-by-step explanation:

2=8 then

8.4x8= 67.2/2= 33.6 feet

3 0

3 years ago